访问所选目录（通过C＃） [英] Access to selected directory (by C#)

问题描述

Hi
通过命令OpenFileDialog（）我可以访问每个路径中的文件。但我想访问目录no to file。我想只获取目录名称作为参数。但是OpenFileDialog（）

获取文件的名称及其路径。

c＃中是否有任何命令用于它？



我该怎么做？

非常感谢

Hi By command "OpenFileDialog()" I can access to a file in every path. But I want to access to directory no to file. I wants to get only name of directory as parameter. But OpenFileDialog()
Get name of file and it’s path.
Is there any command in c# for it?

How can I do this?
Thanks very much

推荐答案

你可以使用 FolderBrowserDialog [ ^ ]类而不是FileDialog。

You can use the FolderBrowserDialog[^] class instead of the FileDialog one.

如果出于某种原因需要使用 OpenFileDialog ，并且建议使用 FolderBrowserDialog Abhinav S还不行，您仍然可以使用 Path.GetDirectoryName <获取文件夹名称/ a> [ ^ ]。

如果你需要在同一个对话框中选择文件夹和/或文件，这可以是一个解决方案： https://github.com/scottwis/OpenFileOrFolderDialog [ ^ ]，但是还有其他解决方案可用于此任务......

If you need to use OpenFileDialog for some reason, and the FolderBrowserDialog suggested by Abhinav S is not enough, you still can get folder name by using Path.GetDirectoryName[^] on the selected file name.
If you need to be able to select folder and/or file in the same dialog, this can be a solution: https://github.com/scottwis/OpenFileOrFolderDialog[^], but there are other solutions too for this task out there...

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