如何在运行时在gridview列中添加图像 [英] How to add image in gridview column at runtime
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问题描述
大家好，
我想在运行时在网格视图中添加图片。我使用以下代码。它的显示错误请求帮助我解决问题。
< asp：GridView ID = gvSpecialist runat = server AutoGenerateColumns = false 宽度 = 965px
onpageindexchanging = gvSpecialist_PageIndexChanging >
< 列 >
< asp：TemplateField HeaderText = 医生姓名 >
< itemtemplate >
< asp：LinkButton ID = lnkNames runat = server ForeColor = black 文字 =' <％＃ Eval（ 名称）％> ' CommandName = 名称 CommandArgument =' <％ #Eval（ 名称）％> ' >
< / itemtemplate >
< itemstyle width = 250px cssclass = gridcol / >
< HeaderStyle HorizontalAlign = 中心 / >
< asp：TemplateField >
< itemtemplate >
< asp：Image ID = Image1 runat = 服务器 ImageUrl =' <％ #BindImage（Eval（ online））< span class =code-pagedirective>％> ' ImageAlign = 左 / >
< / itemtemplate >
< / columns >
< footerstyle backcolor = ＃D4A97F font-bold = True forecolor = 白色 / >
< pagerstyle backcolor = ＃D4A97F forecolor = 黑色 horizontalalign = 中心 >
Wrap =FalseFont-Bold =True/>
< SelectedRowStyle < span class =code-attribute> BackColor = ＃E2DED6 Font-Bold = True ForeColor = ＃333333 / >
< HeaderStyle BackColor = ＃d4a97f Font-Bold = True ForeColor = black
高度 = 30 换行 = 错误 宽度 = 75 / >
< editrowstyle < span class =code-attribute> backcolor = ＃999999 / >
< alternatingrowstyle backcolor = ＃E2D ED6 forecolor = black / >
代码背后：
public string BindImage（ string online）
{
if （online == Y）
{
string imgpath = 〜/ images / Greenflag.png;
return imgpath;
}
else
{
string imgpath = 〜/ images / Redflag.png;
return imgpath;
}
}
但显示错误，因为无法将对象转换为字符串..
请帮助
谢谢
parithi
解决方案
< blockquote>嗨
我认为你必须将参数从object转换为string。
所以你的代码需要改变如下
< span class =code-keyword>< asp：GridView ID = gvSpecialist runat = server AutoGenerateColumns = < span class =code-keyword> false 宽度 = 965px
onpageindexchanging = gvSpecialist_PageIndexChanging >
< 列 >
< asp：TemplateField HeaderText = 医生姓名 >
< itemtemplate >
< asp：LinkButton ID = lnkNames runat = server ForeColor = black 文字 =' <％ #Eval（ 名称）％> ' CommandName = 名称 CommandArgument =' <％ #Eval（ 名称）％> ' >
< / itemtemplate >
< itemstyle width = 250px cssclass = gridcol / >
< HeaderStyle HorizontalAlign = 中心 < span class =code-keyword> / >
< asp：TemplateField < span class =code-keyword>>
< itemtemplate >
< asp：Image ID = Image1 runat = server ImageUrl =' <％ #BindImage（Eval（ online） .ToString（））％ > ' ImageAlign = 左 / >
< / itemtemplate >
< / columns >
< footerstyle backcolor = ＃D4A97F font-bold = True forecolor = 白色 / >
< pagerstyle backcolor = ＃D4A97F forecolor = 黑色 horizontalalign = 中心 >
Wrap =FalseFont-Bold =True/>
我希望这个会帮助你
< asp：TemplateField HeaderText = 缩略图图像 >
< ItemTemplate > < asp：ImageButton ID = imgThumbnail runat = server ImageUrl =' <％＃GetThumbnail（Convert.ToString（DataBinder。 Eval（Container.DataItem， ImagePath））） ％> ' 宽度 = 60px 高度 = 60px AlternateText = Thumbanail Image 工具提示 =' <％＃GetThumbnail（Convert.ToString（DataBinder.Eval） （Container.DataItem， ImagePath）））％ > ' / >
< < span class =code-leadattribute> / ItemTemplate >
< / asp：TemplateField >
public string GetThumbnail（ string strpath）
{
if （！string .IsNullOrEmpty（strpath））
{
string str1 = http：//图像文件夹的虚拟路径/ > + / + strpath。的ToString（）;
return str1;
}
其他
{
返回 ;
}
}
使用图像路径绑定图像字段，然后像这样更新路径：
public void dynimg（）
{
SqlCommand cmd1 = 默认（SqlCommand）;
SqlConnection conn1 = 默认（SqlConnection）;
动态 sql1 = update Rx set url ='images / 1.gif'其中motion = 1;
conn1 = new SqlConnection（ 数据源= 174.142.75.238;初始目录= TDS;用户ID = gac;密码= ffffff）;
cmd1 = new SqlCommand（sql1，conn1）;
conn1.Open（）;
cmd1.ExecuteNonQuery（）;
}
Hi all,
i want to add image in grid view at run time. I am using the following code. its showing error pleas help me to solve the problem .
<asp:GridView ID="gvSpecialist" runat="server" AutoGenerateColumns="false" Width="965px"
onpageindexchanging="gvSpecialist_PageIndexChanging" >
<columns>
<asp:TemplateField HeaderText="Doctor Name">
<itemtemplate>
<asp:LinkButton ID="lnkNames" runat="server" ForeColor="black" Text='<%#Eval("Name")%>' CommandName="Name" CommandArgument='<%# Eval("Name") %>'>
</itemtemplate>
<itemstyle width="250px" cssclass="gridcol" />
<HeaderStyle HorizontalAlign="Center" />
<asp:TemplateField >
<itemtemplate>
<asp:Image ID="Image1" runat="server" ImageUrl='<%# BindImage(Eval("online")) %>' ImageAlign="Left" />
</itemtemplate>
</columns>
<footerstyle backcolor="#D4A97F" font-bold="True" forecolor="White" />
<pagerstyle backcolor="#D4A97F" forecolor="Black" horizontalalign="Center">
Wrap="False" Font-Bold="True" />
<SelectedRowStyle BackColor="#E2DED6" Font-Bold="True" ForeColor="#333333" />
<HeaderStyle BackColor="#d4a97f" Font-Bold="True" ForeColor="black"
Height="30" Wrap="False" Width="75" />
<editrowstyle backcolor="#999999" />
<alternatingrowstyle backcolor="#E2DED6" forecolor="black" />
In code behind:
public string BindImage(string online)
{
if (online == "Y")
{
string imgpath = "~/images/Greenflag.png";
return imgpath;
}
else
{
string imgpath = "~/images/Redflag.png";
return imgpath;
}
}
but it showing error as cannot convert object to string..
please help
thanks
parithi
解决方案
Hi
I think you have to do the convert the parameter from object to string.
So your code need to be altered as below
<asp:GridView ID="gvSpecialist" runat="server" AutoGenerateColumns="false" Width="965px" onpageindexchanging="gvSpecialist_PageIndexChanging" > <columns> <asp:TemplateField HeaderText="Doctor Name"> <itemtemplate> <asp:LinkButton ID="lnkNames" runat="server" ForeColor="black" Text='<%#Eval("Name")%>' CommandName="Name" CommandArgument='<%# Eval("Name") %>'> </itemtemplate> <itemstyle width="250px" cssclass="gridcol" /> <HeaderStyle HorizontalAlign="Center" /> <asp:TemplateField > <itemtemplate> <asp:Image ID="Image1" runat="server" ImageUrl='<%# BindImage(Eval("online").ToString()) %>' ImageAlign="Left" /> </itemtemplate> </columns> <footerstyle backcolor="#D4A97F" font-bold="True" forecolor="White" /> <pagerstyle backcolor="#D4A97F" forecolor="Black" horizontalalign="Center"> Wrap="False" Font-Bold="True" />
I hope this one will help you
<asp:TemplateField HeaderText="Thumbnail Image"> <ItemTemplate> <asp:ImageButton ID="imgThumbnail" runat="server" ImageUrl='<%# GetThumbnail(Convert.ToString(DataBinder.Eval(Container.DataItem,"ImagePath"))) %>' Width="60px" Height="60px" AlternateText="Thumbanail Image " ToolTip='<%# GetThumbnail(Convert.ToString(DataBinder.Eval(Container.DataItem,"ImagePath"))) %>' /> </ItemTemplate> </asp:TemplateField>
public string GetThumbnail(string strpath) { if (!string.IsNullOrEmpty(strpath)) { string str1 = "http://virtual path of images folder/"> + "/" + strpath.ToString(); return str1; } else { return ""; } }
Bind image field with the path of image and then update path like this:
public void dynimg() { SqlCommand cmd1 = default(SqlCommand); SqlConnection conn1 = default(SqlConnection); dynamic sql1 = "update Rx set url='images/1.gif' where motion=1"; conn1 = new SqlConnection("Data Source=174.142.75.238;Initial Catalog=TDS;User ID=gac;Password=ffffff"); cmd1 = new SqlCommand(sql1, conn1); conn1.Open(); cmd1.ExecuteNonQuery(); }
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