将数据集结果，赔率和均值分割为相应的中继器 [英] split dataset results, odds and evens to corresponding repeaters

问题描述

我试图将数据集分成两个中继器，左转发器的几率，右转发器的均衡。我的代码目前只是将两者分开，但我需要赔率为一方而另一方。这是我的代码。提前谢谢！

im trying to split a dataset over two repeaters, odds to left repeater, evens to right repeater. my code at the moment just divides the two, but i need odds to be one side and evens the other. here is my code. thanks in advance!

DataView pageToView = (DataView)pagedRequests.DataSource;        
        
        DataTable leftContent = pageToView.Table.Clone();

        int divide = pagedRequests.Count / 2;



        for (int i = 0; i < divide; i++)
        {
            leftContent.ImportRow(pageToView.Table.Rows[i + pagedRequests.FirstIndexInPage]);
        }

        DataTable rightContent = pageToView.Table.Clone();
        for (int i = divide; i < pagedRequests.Count; i++)
        {
            rightContent.ImportRow(pageToView.Table.Rows[i + pagedRequests.FirstIndexInPage]);
        }


        favRepeaterLeft.DataSource = leftContent;
        favRepeaterLeft.DataBind();

        favRepeaterRight.DataSource = rightContent;
        favRepeaterRight.DataBind();

推荐答案

你可以使用 modulo [ ^ ]运算符检查数字是奇数还是偶数。你可以在你的代码上做这样的事情

You can use the modulo[^] operator to check if a number is odd or even. You can probably do something like this on your code

for(int i = 0; i < pagedRequests.Count; i++)
{
   if(i == 0 || i % 2 == 0) //even
   {
      rightContent.ImportRow(pageToView.Table.Rows[i + pagedRequests.FirstIndexInPage]);
   }
   else //odd
   {
      leftContent.ImportRow(pageToView.Table.Rows[i + pagedRequests.FirstIndexInPage]);
   }
}

这篇关于将数据集结果，赔率和均值分割为相应的中继器的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！