WPF可编辑数据网格 [英] WPF Editable Datagrid
问题描述
您好。
文本框中的用户输入行数和列数,我必须使用此大小创建可编辑的DataGrid。我该怎么做?
DataGrid table = new DataGrid( );
for ( int i = 0 ; i < 5 ; i ++)
{
table.Columns .Add( new DataGridTextColumn());
table.CanUserAddRows = true ;
table.CanUserDeleteRows = true ;
table.IsReadOnly = false ;
table.Items.Add( new DataGridTextColumn());
}
使用此代码我创建了我需要的大小的表,但是当我尝试编辑单元格时,我得到了editItem不允许错误。
如果我执行此代码我会得到带有TextBox字段的列。
DataGrid table = new DataGrid();
列表< TextBox> tableData = new 列表< TextBox>( 5 );
table.ItemsSource = tableData;
任何帮助?
< blockquote>下面我提到你的参考链接请检查..
WPF DataGrid实例 [ ^ ]
如果您找到解决方案然后标记为已回答..
谢谢
快乐编码....
这是关于你的第二个查询的解决方案..
是的你是对的......是的,这是可能的..
public 覆盖 void 执行(对象参数)
{
var context =参数 as GenerateColumnContext;
DataGridTextColumn column = new DataGridTextColumn();
if (context.PropertyName == 国家/地区)
{
column.Header = 国家/地区的标头< /跨度>;
}
context.Result = column;
}
这可以帮助你进一步...
谢谢
如果您得到与此帖相关的答案,请标记为已回答..
Hello.
User input in textboxs number of rows and columns and I have to create editable DataGrid with this size. How can I do this?
DataGrid table = new DataGrid();
for (int i = 0; i < 5; i++)
{
table.Columns.Add(new DataGridTextColumn());
table.CanUserAddRows = true;
table.CanUserDeleteRows = true;
table.IsReadOnly = false;
table.Items.Add(new DataGridTextColumn());
}
With this code I create table with size that I need, but when I try to edit cell, I''he got "editItem not allowed" error.
if I do this code I''he got columns with TextBox fields.
DataGrid table = new DataGrid();
List<TextBox> tableData = new List<TextBox>(5);
table.ItemsSource = tableData;
Any help?
Below i mention link for your reference please check it..
WPF DataGrid Practical Examples[^]
if you finding solution then mark as answered..
Thanks
Happy coding....
This is solution regarding your second query..
yes you are right....yes it is possible..
public override void Execute(object parameter) { var context = parameter as GenerateColumnContext; DataGridTextColumn column = new DataGridTextColumn(); if (context.PropertyName == "Country") { column.Header = "header for Country"; } context.Result = column; }
May be this can help you further...
Thanks
If you getting your answer related to this post then please mark as answered..
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