如何在添加到列表中的任何元素上订阅列表？ [英] How can i subscribe list on any element added to list?

问题描述

你好，

我需要订阅List< T>在添加到列表的任何元素上。我尝试下面的代码，但它不起作用。 （因为订阅已完成，因此初始列表为空）

I need subscribe List<T> on any element added to list. I tried below code but it's not working. (because subscribe completed so initial list is empty)

如何用rx实现我的问题？

How can i implement my problem with rx?

  private void button1_Click(object sender, EventArgs e)
        {
            List<Exception> errors = new List<Exception>();
            var observer = errors.ToObservable();
            observer.Subscribe(err =>
            {
                _txtSummary.AppendText(Environment.NewLine);
                _txtSummary.AppendText(err.ToString());
            });

            for (int i = 0; i < 1000; i++)
            {
                Thread.Sleep(100);
                if (i % 3 == 0)
                    errors.Add(new Exception("yov"));
            }
        }

OğuzhanEren

Oğuzhan Eren

推荐答案

我解决了我的问题（除了：非法交叉线程错误） 如下所示但我不喜欢这个解决方案。  （SelectMany with Interval）

I solve my problem (except: illegal cross thread error) like below but i don't like this solution.  (SelectMany with Interval)

 private void button1_Click(object sender, EventArgs e)
        {
            List<exception> errors = new List<exception>();
            var observer = from t in Observable.Interval(TimeSpan.FromMilliseconds(100))
                           from item in errors.ToObservable()
                           select item;
            
            observer.Subscribe(err =>
            {
                _txtSummary.AppendText(Environment.NewLine);
                _txtSummary.AppendText(err.ToString());
            });

            for (int i = 0; i < 1000; i++)
            {
                Thread.Sleep(100);
                if (i % 3 == 0)
                    errors.Add(new Exception("yov"));
            }
        }</exception></exception>

我需要解决 现在非法交叉线程错误？

I need solve illegal cross thread error now?

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