在MSCRM 4.0中查找当前登录用户 [英] Finding Currently Logged on User in MSCRM 4.0

问题描述

我们正在开发MS CRM 4.0（RTM）。

We are working on MS CRM 4.0 (RTM). 

我们有一个要求，在点击自定义按钮（通过ISV.CONFIG创建）时，我需要找到当前登录用户的用户ID并将其作为查询字符串传递到其中一个URL。

We have a requirement wherein, on click of a custom button (created through ISV.CONFIG), I need to find the currently logged in user's userid and pass it as a querystring to one of the URL.

我尝试了以下Javascript代码，但是它会引发错误...

I tried the following Javascript code, but it throws an error...

//发一个我要求的人
var whoAmIRequest = new RemoteCommand（" SystemUser"，" ; WhoAmI"，" / MSCRMServices /"）;
//执行命令并获取响应
var response = command.Execute（）;
//从响应xml中获取用户ID
var userIdString = response.Xml.text;

//make a who am i request
var whoAmIRequest = new RemoteCommand("SystemUser", "WhoAmI", "/MSCRMServices/");
//execute the command and obtain a response
var response = command.Execute();
//get the user id from the response xml
var userIdString = response.Xml.text;

alert（userIdString）;

alert(userIdString);

这方面的任何帮助都非常有用，非常感谢。

any help in this regard is very helpful and greatly appreciated.

谢谢!!!

推荐答案

< br>尝试这个...
函数GetCurrentUserInfo（）
{

var SERVER_URL =" http：// crm：5555" ;; //替换你的crm服务器名称

var xmlhttp = new ActiveXObject（" Msxml2.XMLHTTP"）;

xmlhttp.open（" POST"，SERVER_URL +" / mscrmservices / 2007 / crmservice.asmx"，false）;

xmlhttp.setRequestHeader（" Content-Type"，" text / xml; charset = utf-8"）;

xmlhttp.setRequestHeader （"SOAPAction"，" http：//schemas.microsoft.com/crm/2007/WebServices/Execute"）;


var soapBody ="< soap：Body>" +

"< Execute xmlns ='http：//schemas.microsoft.com/crm/2007/WebServices'>" +

"< Request xsi：type ='WhoAmIRequest'/>" +

"< /执行>< / soap：Body>" ;;


var soapXml ="< soap ：信封" +

" xmlns oap ='http：// schemas .xmlsoap.org / soap / envelope /'" +

" xmlns：xsi ='http：//www.w3.org/2001/XMLSchema-instance'" +

" xmlns：xsd ='http：//www.w3.org/2001/XMLSchema'>" ;;

soapXml + = GenerateAuthenticationHeader（）;

soapXml + = soapBody ;

soapXml + ="< / soap：Envelope>" ;;

xmlhttp.send（soapXml）;

xmlDoc = new ActiveXObject（&x ; Microsoft.XMLDOM"）;

xmlDoc.async = false;

xmlDoc.loadXML（xmlhttp.responseXML.xml）;

var userid = xmlDoc.getElementsByTagName（" ; UserId"）[0] .childNodes [0] .nodeValue;

// var buid = xmlDoc.getElementsByTagName（" BusinessUnitId"）[0] .childNodes [0] .nodeValue;
< br> // var orgid = xmlDoc.getElementsByTagName（" OrganizationId"）[0] .childNodes [0] .nodeValue;

return userid;

// alert（" UserId： " + userid +&quo t; \r\\\
BusinessUnitId：" + buid +" \\\\ nOrganizationId：" + orgid）;

}

Hi,

Try this...
function GetCurrentUserInfo()
{

var SERVER_URL = "http://crm:5555"; //replace with your crm server name

var xmlhttp = new ActiveXObject("Msxml2.XMLHTTP");

xmlhttp.open("POST", SERVER_URL + "/mscrmservices/2007/crmservice.asmx", false);

xmlhttp.setRequestHeader("Content-Type", "text/xml; charset=utf-8");

xmlhttp.setRequestHeader("SOAPAction", "http://schemas.microsoft.com/crm/2007/WebServices/Execute");


var soapBody = "<soap:Body>"+

"<Execute xmlns='http://schemas.microsoft.com/crm/2007/WebServices'>"+

"<Request xsi:type='WhoAmIRequest' />"+

"</Execute></soap:Body>";


var soapXml = "<soap:Envelope " +

"xmlnsoap='http://schemas.xmlsoap.org/soap/envelope/' "+

"xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' "+

"xmlns:xsd='http://www.w3.org/2001/XMLSchema'>";

soapXml += GenerateAuthenticationHeader();

soapXml += soapBody;

soapXml += "</soap:Envelope>";


xmlhttp.send(soapXml);

xmlDoc=new ActiveXObject("Microsoft.XMLDOM");

xmlDoc.async=false;

xmlDoc.loadXML(xmlhttp.responseXML.xml);

var userid = xmlDoc.getElementsByTagName("UserId")[0].childNodes[0].nodeValue;

//var buid = xmlDoc.getElementsByTagName("BusinessUnitId")[0].childNodes[0].nodeValue;

//var orgid = xmlDoc.getElementsByTagName("OrganizationId")[0].childNodes[0].nodeValue;

return userid;

//alert("UserId: " + userid + "\r\nBusinessUnitId: " + buid + "\r\nOrganizationId: " + orgid);

}

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