为什么onCallStateChanged（）在Android上调用超过一次在一个单一的电话吗？ [英] why onCallStateChanged() on Android is invoked more than one time in a single call？

问题描述

我想实现一个prevents调用，例如防火墙的应用程序。当我调试我的应用程序，我发现，当有在，在 onCallStateChanged（）函数调用接口的 PhoneStateListener 被调用三次。其结果是，preventing可导致三个日志一个呼叫。我很困惑！

我的code：

  @覆盖
    公共无效onCallStateChanged（INT状态，弦乐incomingNumber）{
        尝试{
            如果（状态== TelephonyManager.CALL_STATE_RINGING＆放大器;＆安培;
                PhoneUtil.getITelephony（TPM）.isRinging（））{
                串旗= isBlockCall（myContext，myHelper，myTypes，incomingNumber）;
                如果（flag.length（）大于0）{
                    blockCall（）;
                    myHelper.insertLog（新的String [] {标志，incomingNumber，将String.valueOf（System.currentTimeMillis的（）），空}）;
                    showNotification（myContext，incomingNumber，System.currentTimeMillis的（））;
                }
            }
        }赶上（例外五）{
            e.printStackTrace（）;
        }        super.onCallStateChanged（州，incomingNumber）;
    }
}，PhoneStateListener.LISTEN_CALL_STATE）;
 

解决方案

PinkyJie，

onCallStateChanged（）正在与广播接收器。所以onCallStateChanged（）总是会被调用时呼叫状态得到改变。有三个呼叫状态。

TelephonyManager.CALL_STATE_IDLE：电话处于空闲状态，没有呼叫行动结果。
TelephonyManager.CALL_STATE_OFFHOOK：至少有一个电话是活跃在任何一种结果。
TelephonyManager.CALL_STATE_RINGING：一个新的呼叫到达，振铃或等待。
TelephonyManager。

系统永远不会点到为止。请参考以下链接的http://developer.android.com/reference/android/telephony/TelephonyManager.html

 公共类TestPhoneStateListener扩展PhoneStateListener {  公共无效onCallStateChanged（INT状态，弦乐incomingNumber）{
    // TODO自动生成方法存根
    的System.out.println（aaaaaaaaaaaaaaa ----------------------------------+状态）;
    尝试{
        如果（状态== TelephonyManager.CALL_STATE_RINGING）{
        }
    }赶上（例外五）{
        // TODO自动生成catch块
        e.printStackTrace（）;
    }
    super.onCallStateChanged（州，incomingNumber）;
  }
}
 

I wanted to implement an app that prevents calls like a firewall. When I debug my app, I found that when there is a call in, the onCallStateChanged() function in interface PhoneStateListener is invoked three times. As a result, preventing one call can result in three logs. I'm so confused!!

my code:

    @Override
    public void onCallStateChanged(int state, String incomingNumber) {
        try {
            if (state == TelephonyManager.CALL_STATE_RINGING && 
                PhoneUtil.getITelephony(tpm).isRinging()) {
                String flag = isBlockCall(myContext, myHelper, myTypes, incomingNumber);
                if (flag.length() > 0) {
                    blockCall();
                    myHelper.insertLog(new String[] { flag, incomingNumber, String.valueOf(System.currentTimeMillis()), null });
                    showNotification(myContext, incomingNumber, System.currentTimeMillis());
                }
            }
        } catch (Exception e) {
            e.printStackTrace();
        }

        super.onCallStateChanged(state, incomingNumber);
    }
}, PhoneStateListener.LISTEN_CALL_STATE);

解决方案

PinkyJie,

onCallStateChanged() is working with BroadcastReceiver. so onCallStateChanged() will always get called whenever call state get changed. There are three call states.

TelephonyManager.CALL_STATE_IDLE: Phone is in idle mode, no call action.
TelephonyManager.CALL_STATE_OFFHOOK: At least one call is active in any kind.
TelephonyManager.CALL_STATE_RINGING: A new call arrived and is ringing or waiting. TelephonyManager.

system will never go beyond that. please refer this link http://developer.android.com/reference/android/telephony/TelephonyManager.html

public class TestPhoneStateListener extends PhoneStateListener{

  public void onCallStateChanged(int state, String incomingNumber) {
    // TODO Auto-generated method stub
    System.out.println("aaaaaaaaaaaaaaa----------------------------------"+state);
    try {
        if (state == TelephonyManager.CALL_STATE_RINGING ) {
        }
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    super.onCallStateChanged(state, incomingNumber);
  }
}

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