使用Accessors设置用户名 [英] Using Accessors to set a Users name

问题描述

我有一个继承自Bass类的Character类。在运行时，我希望用户输入字符名称。我想使用SetName访问器来完成此操作。我尝试过多种方法让它发挥作用。我创造了一个新的角色英雄;并尝试传递Hero.SetName（cin，sName）;

哪个不起作用。调试器告诉我sName没有在main.cpp文件的范围内声明。我的问题是如何使用Set访问器获取用户名并保持封装的主要内容。我可以为My heros名称传递一个全局变量，但是我失去了封装的好处。我的Main.cpp文件和Charecter类发布在下面谢谢。

 #include <   iostream  >  
 #include <   string  >  
 #include <   cstdlib  >  
 #include <   cmath  >  
 #include <   ctime  >  
 
 #includeCharacterClass.h使用namespace std 
 
; 
 
 int main（）
 {
 srand（time（0））; 
 CharecterClass Hero; 
 cout <  <    输入   您的   名称   挑战者：   ;   
   
   
   
        < span class =code-attribute>   // system（cls）;   
   
   
   
           Hero.SetName（cin，    sName）;   
   
           Hero.SetHealth（5）;   
  < span class =code-attribute> 
           Hero.SetAttack（（rand（）％    12）    +     1）;   
   
   
   
           cout    <<     Hero.GetName（）   <<     endl;   
   
           cout    < <     Hero.GetHealth（）   <<     endl;   
   
           cout    <<     Hero.GetAttack（）   << ;     endl;   
   
           return     0;   
   
  }  

  #ifndef CHARACTERCLASS_H 
   #define CHARACTERCLASS_H 
  
 #include   BaseClass。 h 
 #include< iostream> 
 
 
  class  CharacterClass： public  BaseClass 
 { 
  public ：
 CharacterClass（）; 
  virtual  ~CharacterClass（）; 
 
  int  GetArmor（）{ return  m_CharacterArmor; } 
  int  GetAttack（）{ return  m_CharacterAttack; } 
  int  GetDamage（）{ return  m_CharacterDamage; } 
 
  void  SetArmor（ int  nCharacterArmor）{m_CharacterArmor = nCharacterArmor; } 
  void  SetAttack（ int  nCharacterAttack）{m_CharacterAttack = nCharacterAttack; } 
  void  SetDamage（ int  nCharacterDamage）{m_CharacterDamage = nCharacterDamage; } 
 
 
 
 受保护：
 私人：
  int  m_CharacterArmor; 
  int  m_CharacterAttack; 
  int  m_CharacterDamage; 
}; 
 
 ＃endif // CHARACTERCLASS_H  

  #ifndef BASECLASS_H 
   #define BASECLASS_H 
  
 #include< iostream> 
 
  class  BaseClass 
 {
  public ：
 BaseClass（）; 
  virtual  ~BaseClass（）; 
 
 std ::  string  GetName（）{ return  m_Name; } 
  int  GetHealth（）{ return  m_Health; } 
 
 
  void  SetName（std ::  string  sName） {m_Name = sName; } 
  void  SetHealth（ int  nHealth）{m_Health = nHealth; } 
 
 
 受保护：
 私人：
 std ::  string  m_Name; 
  int  m_Health; 
 
 
}; 
 
 ＃endif // BASECLASS_H  

解决方案

要使用我的访问器设置名称，我创建了一个带有本地字符串变量的函数，我将返回Hero.SetName（）。这对我保持我的课程封装起来很有用。



string HeroName（）

{

string sTemp;

cout<< 输入你的名字挑战者：;

cin>> STEMP;

返回sTemp;

}



这是它的实施



Hero .SetName（HeroName（））;

I Have a Character class that inherits from a Bass class. At run time I want the user to enter the characters name. I want to do this using the SetName Accessor. I''ve tried multiple ways to get this to work. I created a new Character Hero; and tried to pass Hero.SetName(cin, sName);
Which did not work. The debugger tells me that sName is not declared in the scope of my main.cpp file. My question is is how do I go about getting a users name using the Set accessor and keeping with the pricipal of encapsulation. I can pass a global variable for My heros name but I lose the benefit of encapsulation. My Main.cpp file and Charecter class are posted below thanks.

#include <iostream>
#include <string>
#include <cstdlib>
#include <cmath>
#include <ctime>

#include "CharacterClass.h"

using namespace std;

int main()
{
    srand(time(0));
    CharecterClass Hero;
    cout << "Enter your name Challenger: ";



    //system("cls");



    Hero.SetName(cin, sName);

    Hero.SetHealth(5);

    Hero.SetAttack((rand()% 12) + 1);



    cout << Hero.GetName() << endl;

    cout << Hero.GetHealth() << endl;

    cout << Hero.GetAttack() << endl;

    return 0;

}

#ifndef CHARACTERCLASS_H
#define CHARACTERCLASS_H

#include "BaseClass.h"
#include <iostream>


class CharacterClass : public BaseClass
{
    public:
        CharacterClass();
        virtual ~CharacterClass();

        int GetArmor() { return m_CharacterArmor; }
        int GetAttack() { return m_CharacterAttack; }
        int GetDamage() { return m_CharacterDamage; }

        void SetArmor(int nCharacterArmor) { m_CharacterArmor = nCharacterArmor; }
        void SetAttack(int nCharacterAttack) { m_CharacterAttack = nCharacterAttack; }
        void SetDamage(int nCharacterDamage) { m_CharacterDamage = nCharacterDamage; }



    protected:
    private:
        int m_CharacterArmor;
        int m_CharacterAttack;
        int m_CharacterDamage;
};

#endif // CHARACTERCLASS_H

#ifndef BASECLASS_H
#define BASECLASS_H

#include <iostream>

class BaseClass
{
    public:
        BaseClass();
        virtual ~BaseClass();

        std::string GetName() { return m_Name; }
        int GetHealth() { return m_Health; }


        void SetName(std::string sName) { m_Name = sName; }
        void SetHealth(int nHealth) { m_Health = nHealth; }


    protected:
    private:
        std::string m_Name;
        int m_Health;


};

#endif // BASECLASS_H

解决方案

To set the name using my accessor I created a function with a local string variable which I return to Hero.SetName(). This worked for me keeping my class encapsulated.

string HeroName()
{
string sTemp;
cout << "Enter your name challenger:";
cin >> sTemp;
return sTemp;
}

and here is it''s implementation

Hero.SetName(HeroName());

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