查找相关的ImageView的位置，它的显示图像 [英] Find position of ImageView relative to the image it's displaying

问题描述

所以这里的问题。我在显示一个ImageView的大图，并需要找到它相对于图像的位置。像这样的：

<$p$p><$c$c>╔═══════════════════════════════╗
║║图像
║──＆GT;╔═════════════╗║
║║ImageView的║║
║║║║
║╚═════════════╝║
║║
║║
╚═══════════════════════════════╝

任何帮助吗？

UPD：由于有一些误解，我会详细解释这个问题。

我有一个形象。位图实际。我在ImageView的与中心规模型显示它。假定图像比ImageView的更大，所以只显示图像的一部分。我想找到这相对于整个图像部分的位置。

解决方案

共达（），getLeft（）的子视图不会解决它？
如果意见不父子，但具有相同的父 - 这样做对每个视图和做数学题

So here's the problem. I am displaying a big image in ImageView and need to find it's position relative to the image. Like this:

╔═══════════════════════════════╗
║ Image                         ║ 
║──>╔═════════════╗             ║
║   ║ ImageView   ║             ║
║   ║             ║             ║
║   ╚═════════════╝             ║
║                               ║
║                               ║
╚═══════════════════════════════╝

Any help?

UPD: Since there were some misunderstandings I will explain the problem in detail.

I have an image. A Bitmap actually. I am displaying it in an ImageView with CENTER scale type. Assume that the image is bigger than the ImageView, so only a part of the image is displayed. I want to find the position of this part relative to the whole image.

解决方案

getTop() , getLeft() on the child view won't solve it ? And if views are not parent-child , but have same parent - do it for each view and do the math

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