分配函数的返回IEnumerable< MovingAverage>价值到另一个对象 [英] Assign a function's returned IEnumerable<MovingAverage> value to another object

问题描述

我正在调用这个函数：

    私人   静态    IEnumerable  <   MovingAverage  >     SimpleMovingAverage  （  
   IEnumerable  <   IexTradingStock  >    队列 ，    int  句号 ）  
  。  
  。   （ 省略代码 ）  
  。  
   {   返回  movingAverages  ;   

这是调用MovingAverage的函数：

     MovingAverage   SMA   =    新    MovingAverage  （）;   
 SMA   =     SimpleMovingAverage  （  stocks  ， < span class ="pln"style ="margin：0px; padding：0px; border：0px; font-style：inherit; font-variant：inherit; font-weight：inherit; line-height：inherit; font-family：inherit ; vertical-align：baseline; color：＃303336"> period  ）;   

我在这一行收到错误"SMA = SimpleMovingAverage（stocks，period）;"错误是"无法隐式转换类型'System.Collections.Generic.IEnumerable'到' myBackEnd.Models.MovingAverage'存在显式转换（你错过
a cast）

解决方案

< blockquote>

你正在返回它看起来的多个对象，所以你应该有 IEnumerable< MovigngAverage> 
来保存对该对象的引用。试试如下：

 IEnumerable< MovingAverage> SMA = SimpleMovingAverage（股票，期间）; 

如果要返回单个对象，则需要更改方法的返回类型：

 private static MovingAverage SimpleMovingAverage（
 IEnumerable< IexTradingStock> queue，int period）
 {
 // code here 
 
 return movignAeverage; 
} 

现在你应该可以这样做：

 MovingAverage = SimpleMovingAverage（股票，期间）; 

希望有所帮助！

I am calling this function:

        private static IEnumerable<MovingAverage> SimpleMovingAverage(
        IEnumerable<IexTradingStock> queue, int period)
        .
        . (omitted code) 
        .
    {   return movingAverages;

This is the function that calls MovingAverage:

                MovingAverage SMA = new MovingAverage();
            SMA = SimpleMovingAverage(stocks, period);

I get an error on this line "SMA = SimpleMovingAverage(stocks, period);" The error is "Cannot implicitly convert type 'System.Collections.Generic.IEnumerable' to 'myBackEnd.Models.MovingAverage' an explicit conversions exists (are you missing a cast)

解决方案

You are returning multiple objects it seems like, so you should have IEnumerable<MovigngAverage>  to hold the reference to that object. Try like following :

 IEnumerable<MovingAverage> SMA = SimpleMovingAverage(stocks, period);

and if you are returning a single object, then you need to change the return type of the method :

private static MovingAverage SimpleMovingAverage(
        IEnumerable<IexTradingStock> queue, int period)
{
   // code here

   return movignAeverage;
}

and now you should be able to do :

MovingAverage = SimpleMovingAverage(stocks, period);

Hope it helps!

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