将Int增加1％ [英] Increasing Int by 1%

问题描述

我有一个var作为Int，包含多个计算用作Int数字（不是双数等）。 b $ b和var等于，应该增加该值的1％。

I have a var as an Int that includes multiple calculations to be used as an Int number (not a double, etc.)
and whatever the var equals, should be increased by 1% of that value.

我在代码中达到了以下内容，但我觉得有些不对劲：

I've reached the following in my code, but I feel something wrong:

int IncreaseBy = 0; // the number is only 1 ~ 10%

var result = (int)(/* some numbers */
                          (/*also numbers*/ + IncreaseBy * 0.100);

Console.WriteLine("Result: " + result.ToString());

是的，我知道它可能正在工作，但它可能并不意味着它是正确的，我希望这个没有双打，并且100％正确。

Yes, I know its probably working but it may not mean its correct,
I want this to be with no doubles, and 100% correct.

如果" IncreaseBy"是0？，是
它还会增加吗？因为如果它是0％，我不希望它增加。

and what if the "IncreaseBy" is 0 ?,
will it still increase ? because I don't want it to be increased if it was 0% by any chance.

谢谢事先。

推荐答案

你好， 

Hello, 

>  我希望这与没有双打，100％正确。

> I want this to be with no doubles, and 100% correct.

Ok。 

您的原始值等于"1"并且您的需求准确地增加了"2％"。

< span style ="color：＃333333; font-family：'Segoe UI'，'Lucida Grande'，Verdana，Arial，Helvetica，sans-serif;字体大小：14px的; line-height：20.162px">你有几个选择：

- 0

- 1

- 2

0和1之间没有任何内容。  1和2之间也没有任何内容。

And there is nothing between 0 and 1. There also nothing between 1 and 2.

哪个结果100％正确？

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