通过捆绑到if语句 [英] Pass bundle to if-statement
问题描述
活动索赔---->有2 按钮和的TextView （获得总金额）
Activity Claims----> has 2 button and a textView (get the total amount)
活动PROJECT1和汽油----->有一个 EDITTEXT 和保存按钮
Activity Project1 and Petrol-----> one editText and a save button
活动声明
button1.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
AlertDialogRadio(a1);
}
});
button2.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
AlertDialogRadio(a2);
}
});
public void AlertDialogRadio(final int k) {
final CharSequence[] ClaimsModel = {"Project1", "Petrol"};
AlertDialog.Builder alt_bld = new AlertDialog.Builder(getActivity());
alt_bld.setTitle("Select a Claims");
alt_bld.setSingleChoiceItems(ClaimsModel, -1, new DialogInterface
.OnClickListener() {
public void onClick(DialogInterface dialog, int item) {
if (item == 0) {
Intent intent = new Intent(getActivity().getApplicationContext(), Project1.class);
intent.putExtra("k",k);
startActivityForResult(intent, 0);
} else if (item == 1) {
Intent intent = new Intent(getActivity().getApplicationContext(), Petrol.class);
intent.putExtra("k", k);
startActivityForResult(intent, 1);
}
**无论PROJECT1或汽油，取决于...）**
** Either Project1 or Petrol, depends...)**
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.project);
text= (EditText)findViewById(R.id.editText1);
Button save=(Button)findViewById(R.id.button12);
save.setOnClickListener(new View.OnClickListener() {
public void onClick(View arg0) {
Intent returnIntent = new Intent();
l="A";
text = text.getText().toString();
returnIntent.putExtra("text", text);
returnIntent.putExtra("l", l);
final int k1 = getIntent().getExtras().getInt("k");
returnIntent.putExtra("k1", k1);
setResult(Activity.RESULT_OK, returnIntent);
finish();
}
});
}
@Override
public void onBackPressed()
{
Intent returnIntent = new Intent();
setResult(Activity.RESULT_CANCELED, returnIntent);
finish();
}
是否有可能通过一个捆绑到 if语句？我想将值传递给另一例，最终总量可达两个值。我怎样才能做到这一点？现在，我只得到了价值为和 BS ，而不是价值金额。我相信它需要添加一个捆绑双方 if语句 ...
Is it possible to pass a bundle to if statement? I want to pass a value to another cases and finally total up the two values. How can I achieve this? Now I only get the value as and bs, but not value amount. I do believe it need to add a bundle to both if statement...
继续Claims.java ....
public void onActivityResult(int requestCode, int resultCode, Intent data) {
int button = data.getIntExtra("k1", 0); // to check which button was pressed
long a=0;
long as=0;
long bs=0;
String result;
String result1;
if (button == 1) {
switch (requestCode) {
case 0:
result = data.getStringExtra("text");
String b = data.getStringExtra("l");
as=Long.parseLong(result);
c.setText(" " + b + "------" + "RM " + result);
Toast.makeText(getActivity(),as+"", Toast.LENGTH_LONG).show();
break;
case 1:
result = data.getStringExtra("text");
String b1 = data.getStringExtra("l");
as=Long.parseLong(result);
c.setText(" " + b1 + "------" + "RM " + result);
Toast.makeText(getActivity(),as+"", Toast.LENGTH_LONG).show();
break;
}
if(button==2)
{
switch (requestCode) {
case 0:
result1 = data.getStringExtra("text");
String b = data.getStringExtra("l");
bs=Long.parseLong(result1);
d.setText(" " + b + "------" + "RM " + result1);
Toast.makeText(getActivity(),bs+"", Toast.LENGTH_LONG).show();
break;
case 1:
result1 = data.getStringExtra("text");
String b1 = data.getStringExtra("l");
bs=Long.parseLong(result1);
d.setText(" " + b1 + "------" + "RM " + result1);
Toast.makeText(getActivity(),bs+"", Toast.LENGTH_LONG).show();
break;
}
}
else if(requestCode==CAMERA_REQUEST_CODE)
{
}
long amount=as+bs;
Toast.makeText(getActivity(),amount+"", Toast.LENGTH_LONG).show();
我指<一个href=\"http://stackoverflow.com/questions/10901709/how-can-i-pass-a-string-value-that-has-been-created-in-an-if-statement-through\">How我可以传递一个字符串值，已在if语句中被创建，通过捆绑内的另一个if语句？但得到的答复是还不是很清楚我。
I refer How can i pass a string value, that has been created in an if statement, through a bundle inside another if statement? but the answer is quite unclear for me.
索赔的图片
![！[在这里输入的形象描述](\"http://i.stack.imgur.com/nDuKA.png\")
的敬酒应显示1 12 13，但我得到1 12 12。这似乎是值 1 不能添加！
The toast should display 1 12 13 but I get 1 12 12. It seems like the value 1 cannot be added!
推荐答案
您应该直接存储你在你的onActivityResult在活动的变量传递的值，然后读取这些变量的吐司。
You should store the values you get passed in your onActivityResult in a variable of your Activity, and then directly read these variables for the Toast.
public class Claims{
long a, as, bs;
public void onActivityResult(int requestCode, int resultCode, Intent data) {
int button = data.getIntExtra("k1", 0);
String result;
if (button == 1) {
result = data.getStringExtra("text");
as=Long.parseLong(result);
} else if(button==2) {
result = data.getStringExtra("text");
bs=Long.parseLong(result1);
}
long amount=as+bs;
Toast.makeText(getActivity(),amount+"", Toast.LENGTH_LONG).show();
}
}
您还需要根据自己的标准，虽然初始化你的价值观。
You still need to initialise your values according to your standards though.
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