MFC中对话框上的线图 [英] Line Graph on Dialog Box in MFC

问题描述

Hello Everyone .. !!



任何人都可以告诉我如何在MFC中的对话框上绘制线图。

我有一个带有一些值的数组，我需要使用这些值生成一个图形。我应该使用哪种MFC工具/类？我以前从未在图表上工作，所以请人们帮帮我....

Hello Everyone..!!

Can anyone please tell me how to draw a line graph on a dialog box in MFC.
I have an array with some values and I need to generate a graph using those values. Which MFC Tool / Class should I use? I have never worked on graphs before so please people help me out....

推荐答案

我不确定是否有一个简单的MFC类来执行此操作。您可以使用静态控制 [ SS_OWNERDRAW ^ ] c>财产。然后，您可以在 WM_DRAWITEM 消息 [ ^ ] 。

I am not sure if there is a simple MFC class to do this. You can do it with a Static Control[^] in your dialog that has the SS_OWNERDRAW property. You can then add your lines in the handler for the WM_DRAWITEM message[^].

您可以使用图形基元（ GDI OnPaint 处理程序中） c>或 GDI + ）或者您可以使用图表控件，例如，Cedric的高速制图控制 [ ^ ]。



[更新]

假设你有一个坐标数组，想要创建一个线性图。

首先你必须找到 xmin，xmax，ymin，ymax 为了缩放（和平移）所有坐标以适应屏幕矩形你打算使用：

You may draw yourself (in OnPaint handler) using graphic primitives (GDI or GDI+) or you may use a chart control, like, for instance, Cedric''s High-speed Charting Control[^].

[Update]
Suppose you have an array of coordinates and want to create a linear graph.
First you have to find xmin, xmax, ymin, ymax in order to scale (and translate) all the coordinates to fit into the screen rectangle you intend to use:

x[i] = rcx + rcwidth/(xmax-xmin)* x[i];
y[i] = rcy - rcheight/(ymax-ymin)* y[i];

其中 rcx，rcy 是屏幕矩形左上角的坐标， rcwidth，rcheight 是它的尺寸。

最后你有绘制连接连续点的所有线，例如

where rcx, rcy are the coordinates of the top-left point of the screen rectangle and rcwidth,rcheight are its dimensions.
Finally you have to draw all the lines connecting successive points, e.g.

MoveToEx(hdc, x[0], y[0]);
for(n=1; n<N; ++n)
  LineTo(hdc, x[n], y[n]);

[/ Update]

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