从asmx webservice获取XML文档并在gridview中显示它? [英] Getting XML document from asmx webservice and displaying it in gridview?

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本文介绍了从asmx webservice获取XML文档并在gridview中显示它?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

从海报工具我得到的数据库作为xml标签的值我怎么能通过前端的gridview在表单中显示????



TestService.Service wsTestService = new TestService.Service(); //表单连接到webservice

XmlDocument document = new XmlDocument();

System.Xml.XmlNode newNode;

newNode = wsTestService.GetDataFromDB ();

DataSet ds = new DataSet();

byte [] buf = System.Text.ASCIIEncoding.ASCII.GetBytes(newNode.OuterXml);

System.IO.MemoryStream ms = new System.IO.MemoryStream(buf);

ds.ReadXml(ms);

dataGridView1.DataSource = ds .Tables [0];

//dataGridView1.DataBind();

string Msg = string.Empty;

int Suc;

字符串Role =student;

wsTestService.FACULTIES_ONLINE(角色,文档,out Msg,out Suc); //文件是xml文件我怎么称呼它?

解决方案

显示为XmlNode节点(对象)



DataTable dt = new DataTable();

dt.Columns.Add(FirstName,typeof(string));

dt.Columns.Add( LastName,typeof(string));

dt.Columns.Add(UserName,typeof(string));

dt.Columns.Add(Role ,typeof(string));

XmlDocument xmldoc = new XmlDocument();

xmldoc.Load(Server.MapPath(SampleXML.xml));

XmlNodeList nodeList = xmldoc.SelectNodes(/ users / user);

foreach(nodeList中的XmlNode节点)

{

DataRow dtrow = dt.NewRow();

dtrow [FirstName] = node [FirstName]。InnerText;

dtrow [LastName] = node [LastName]。InnerText;

dtrow [UserName] = node [UserName]。InnerText;

dtrow [Role] = node [ 工作] [角色] .InnerText;

dt.Rows.Add(dtrow);

}

gvDetails.DataSource = DT;

From poster tool i got the values from DB as xml tags how could i display in the form through gridview in front end????

TestService.Service wsTestService = new TestService.Service(); // form connected to webservice
XmlDocument document = new XmlDocument();
System.Xml.XmlNode newNode;
newNode = wsTestService.GetDataFromDB();
DataSet ds = new DataSet();
byte[] buf = System.Text.ASCIIEncoding.ASCII.GetBytes(newNode.OuterXml);
System.IO.MemoryStream ms = new System.IO.MemoryStream(buf);
ds.ReadXml(ms);
dataGridView1.DataSource = ds.Tables[0];
//dataGridView1.DataBind();
string Msg = string.Empty;
int Suc;
string Role = "student";
wsTestService.FACULTIES_ONLINE( Role ,out document, out Msg, out Suc); // document is xml document how could i call it??

解决方案

Display as XmlNode Node(object)

DataTable dt = new DataTable();
dt.Columns.Add("FirstName", typeof(string));
dt.Columns.Add("LastName", typeof(string));
dt.Columns.Add("UserName", typeof(string));
dt.Columns.Add("Role", typeof(string));
XmlDocument xmldoc = new XmlDocument();
xmldoc.Load(Server.MapPath("SampleXML.xml"));
XmlNodeList nodeList = xmldoc.SelectNodes("/users/user");
foreach (XmlNode node in nodeList)
{
DataRow dtrow = dt.NewRow();
dtrow["FirstName"] = node["FirstName"].InnerText;
dtrow["LastName"] = node["LastName"].InnerText;
dtrow["UserName"] = node["UserName"].InnerText;
dtrow["Role"] = node["Job"]["Role"].InnerText;
dt.Rows.Add(dtrow);
}
gvDetails.DataSource = dt;


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