如何进行侧栏转换？ [英] How to make the sidebar transition?

问题描述

我有一个简单的splitview，其宽度为4px，表示spiltview中的所选项目。



  &NBSP; < Rectangle Horizo​​ntalAlignment =" Left" VerticalAlignment =" Top" 

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP;宽度=" 4英寸高度= QUOT; 48英寸;保证金=< 1,0"

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP;   Fill =" {ThemeResource SystemAccentColor}" Grid.Row =" 2"

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP;   Visibility =" {x：Bind btnHome.IsChecked，Mode = OneWay}" />

zh
现在我打开/关闭了多个矩形取决于是否选中了复选框！但相反，我希望我的代码中有一个矩形，它应该从之前的位置过渡到用户点击的位置。

I have a simple splitview that has a rectangle of width 4px that indicates the selected item in the spiltview.

    <Rectangle HorizontalAlignment="Left" VerticalAlignment="Top" 
                               Width="4" Height="48" Margin="1,0"
                               Fill="{ThemeResource SystemAccentColor}" Grid.Row="2"
                               Visibility="{x:Bind btnHome.IsChecked, Mode=OneWay}"/>

Right now I've multiple rectangles turned on/off depending whether the checkbox is selected or not! But instead, I want a single rectangle in my code that should transition from the place where it previously was to place where the user has clicked.

推荐答案

你好D12UWP，

Hi D12UWP,

根据你的问题与UWP有关，我会把线程移到  开发通用Windows应用论坛以获得合适的支持。

According to your question is more related to UWP, I will move the thread to Developing Universal Windows apps forum for suitable support.

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最好的问候，

feih-7

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