检查表单是否已打开C＃ [英] Check if form is already opened C#

问题描述

您好，

我有一个包含3个组合框的表单，根据父项和一个按钮填充其他项目。

点击事件另一个表单根据组合框中的选定项目打开。

我想检查表单是否已经打开，而不是从同一个选项中打开另一个表单。

I have one form with 3 comboboxes that populate eachother items based on the parent one and a button.
On click event another form opens based on selected item from the combobox.
I would like to check whether the form is already opened and not open another from the same selected item.

我这样做了

var sensor = new Sensor();
            sensor = comboBoxSensor.SelectedItem as Sensor;

            if (sensor.SensorType == "Fire")
            {
                fireSensorId = sensor;
                var fire = FireSensor.GetInstance();
                fire.Show();
            }

GetInstance（）方法确保一次只打开同一项的1种形式。

the GetInstance() method ensures that only 1 form of same item is opened at a time.

public static FireSensor GetInstance()
        {
            if (instance == null)
            {
                instance = new FireSensor();
            }
            else
            {
                instance.BringToFront();
            }
            return instance;
        }

然而，此当前支票 - "火"可能存在于不同的场景中（不同的父组合框选择）



这就是为什么我想根据组合框valueMember进行第二次检查，这将是传感器ID。

However this current check - "Fire" could exist in different scenarios (different parent combobox selection)

That's why I want to do 2nd check based on the combobox valueMember which would be the sensor ID.

所以我想让几个"Fire"实例成为可能。只有他们有不同的ID。如果不是我不想打开更多。我有点被困在这里，任何建议或帮助表示赞赏。谢谢！

So I want to make it possible to have several instances of "Fire" only if they have different ID. If not I don't want to open more. I am kind of stuck here, any suggestions or help is appreciated. Thank you!

推荐答案

我首先要完成方法中的所有工作。类似于：

I would start by doing all of the work in the method. Something like:

            if (sensor.SensorType == "Fire") { NewGetInstance(); }

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