如何通过单击文件从上下文菜单接收命令？ [英] How to receive command from context menu by clicking on file?

问题描述

这是在指定文件的上下文菜单中创建项目的func。

如何获取被单击的文件路径？谢谢。

Here is the func that create item in context menu of specified file.
How to get path of file, which was clicked? Thanks.

using Microsoft.Win32;
//Extension - Extension of the file (.zip, .txt etc.)
//MenuName - Name for the menu item (Play, Open etc.)
//MenuDescription - The actual text that will be shown
//MenuCommand - Path to executable
private bool AddContextMenuItem(string Extension,
  string MenuName, string MenuDescription, string MenuCommand)
{
  bool ret = false;
  RegistryKey rkey =
    Registry.ClassesRoot.OpenSubKey(Extension);
  if(rkey != null)
  {
    string extstring = rkey.GetValue("").ToString();
    rkey.Close();
    if( extstring != null )
    {
      if( extstring.Length > 0 )
      {
        rkey = Registry.ClassesRoot.OpenSubKey(
          extstring,true);
        if(rkey != null)
        {
          string strkey = "shell\\" + MenuName + "\\command";
          RegistryKey subky = rkey.CreateSubKey(strkey);
          if(subky != null)
          {
            subky.SetValue("",MenuCommand);
            subky.Close();
            subky = rkey.OpenSubKey("shell\\" +
              MenuName, true);
            if(subky != null)
            {
              subky.SetValue("",MenuDescription);
              subky.Close();
            }
            ret = true;
          }
          rkey.Close();
        }
      }
    }
  }
  return ret;
}

推荐答案

if(subky != null)
{
   subky.SetValue("",MenuCommand + " \"%1\");
   ...
}

％1 会给你选择的文件名

The "%1" will give you the filename which was selected

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