有人可以帮我完成这项功课。 [英] Could someone help me with this homework.

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问题描述

所以我必须像这样定义两个var


{double a,b;


Console.Write(定义A: )


a = Convert.ToDouble(Console.ReadLine());


Console.Write(定义B:)


a = Convert.ToDouble(Console.ReadLine());


/////问题从这里开始


I需要插入这样的公式


A ^ 2 -B ^ 2 =(AB)*(A + B)


但预期输出看起来像这个


定义A:4


定义B:2


4 ^ 2 - 2 ^ 2 = < 4-2> *< 4 + 2>


16 - 4 =< 2> *< 6>


12 = 12


不仅仅是12 = 12









}

解决方案


>我需要插入这样的公式



> A ^ 2 -B ^ 2 =(AB)*(A + B)



你不能"插入公式" 。 



您需要为计算机添加一组指令来计算结果。

 double c = a ^ 2 + b ^ 2; 
double d =(a-b)*(a + b);

并对计算结果做一些事情。


Xmmm ... C#是区分大小写的语言 - 'a '和'A'是这种语言的两个不同的东西。






So i have to define two var like this

{ double a,b;

Console.Write (Define A : )

a = Convert.ToDouble (Console.ReadLine());

Console.Write (Define B: )

a = Convert.ToDouble (Console.ReadLine());

/////And problem starts here

I need to insert formula like this

A^2 -B^2 = (A-B)*(A+B)

but expected output looks like this

Define A : 4

Define B: 2

4^2 - 2^2 = <4-2>*<4+2>

16 - 4 = <2>*<6>

12 = 12

not simply 12=12


}

解决方案

> I need to insert formula like this

> A^2 -B^2 = (A-B)*(A+B)

You can't "insert formula". 

You need to put a set of instructions for computer to calculate a result.

double c = a ^ 2 + b ^ 2;
double d = (a-b) * (a+b);

and do something with result of calculations.

Xmmm... C# is case-sensitive language - 'a' and 'A' are two different things in this language.



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