从Sql server 2008中的文本获取整数值 [英] Getting the Integer Values from Text in Sql server 2008
本文介绍了从Sql server 2008中的文本获取整数值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
大家好,
我在表格中有一个列,其中包含三种组合的值
i)整数值(例如6361)
2)整数值后跟两个字母(例如AA6063)
3)整数值后跟三个字母(例如RDE40)
现在我只需要在sql查询中获取整数值。
我想要的结果是上面提到的例子为
i)6361
ii)6063
iii)40
如何在Sql Server 2008中获取它
谢谢...
Hi All,
I have a column in a table which has the values in three combinations
i)Integer values(e.g 6361)
2)Integer values followed by two alphabets (e.g AA6063)
3)Integer values followed by three alphabets (e.g RDE40)
Now i need to get only the integer values in sql query.
I want the results for the above mentioned examples as
i) 6361
ii) 6063
iii) 40
How to get it in Sql Server 2008
Thanks...
推荐答案
访问解决方案的链接
SQL SERVER - 从字母数字字符串中获取数字值 - 仅用于获取数字数字的UDF [ ^ ]
快乐编码!
:)
visit link for solution
SQL SERVER – Get Numeric Value From Alpha Numeric String – UDF for Get Numeric Numbers Only[^]
Happy Coding!
:)
Solution1非常好,但使用循环。或者,您可以尝试这样的事情:
Solution1 is very good, but uses loops. Alternatively, you can try something like this:
DECLARE @tmp TABLE (someText VARCHAR(30))
INSERT INTO @tmp (someText)
VALUES('6361')
INSERT INTO @tmp (someText)
VALUES('AA6063')
INSERT INTO @tmp (someText)
VALUES('RDE40')
SELECT someText, CONVERT(INT, SUBSTRING(someText, StartPos, EndPos)) AS MyNumeric
FROM(
SELECT someText, PATINDEX('%[0-9]%',someText) AS StartPos, CASE
WHEN PATINDEX('%[A-Za-z]%',SUBSTRING(someText, PATINDEX('%[0-9]%',someText) +1, LEN(someText)-PATINDEX('%[0-9]%',someText)))=0 THEN LEN(someText)
ELSE PATINDEX('%[A-Za-z]%',SUBSTRING(someText, PATINDEX('%[0-9]%',someText) +1, LEN(someText)-PATINDEX('%[0-9]%',someText)))
END AS EndPos
FROM @tmp) AS T
结果:
Result:
someT.. MyNumeric
6361 6361
AA6063 6063
RDE40 40
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