如何在结果中包含字段。 RIA服务 [英] How do you include a field in your result. RIA Services
问题描述
表: 条件
ConditionId
描述
PersonId
表:人士
PersonId
名称
当我通过ria服务检索条件时,它不会包含Person表,只包含PersonId。
当我选择使用include方法时,它会失败。
任何想法?
你好,
欢迎来到EF论坛!
您能否向我们提供有关您遇到的问题的更多详细信息?
在包含相关实体时,您遇到的错误或异常是什么?
此外,这里有关于构建WCF RIA服务的参考资料的优秀教程,
http://www.silverlightshow.net/items/Building -N-tier-business-applications-with-WCF-RIA-Services-Part-II.aspx 。   
此外,对于RIA服务问题,您也可以咨询RIA服务论坛,
http://forums.silverlight.net/forums/53.aspx
度过愉快的一天!
最诚挚的问候,b
Lingzhi Sun
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Table: Condition
ConditionId
Description
PersonId
Table: Person
PersonId
Name
When I retrieve the conditon over ria services, it does not inlcude the Person table, only the PersonId.
When I select use the include method it fails.
Any ideas?
Hello,
Welcome to EF forum!
Could you please provide us with more detailed information about the issue you encountered? What’s the error or exception do you meet when including the related entities? Besides, here is a great tutorial for your references about building a WCF RIA services, http://www.silverlightshow.net/items/Building-N-Tier-business-applications-with-WCF-RIA-Services-Part-II.aspx.
Also, for RIA Services issues, you can consult the RIA Service forum as well, http://forums.silverlight.net/forums/53.aspx
Have a nice day!
Best Regards,
Lingzhi SunMSDN Subscriber Support in Forum
If you have any feedback on our support, please contact msdnmg@microsoft.com
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