如何将Byte数组转换为Long [英] How to convert Byte array to Long

问题描述

如何将Byte数组转换为Long？



这里我有一个字节数组

How to convert Byte array to Long?

Here I have i array of the byte

bytDataReceived(0)=76
bytDataReceived(1)=116
bytDataReceived(2)=157
bytDataReceived(3)=77

现在 bytDataReceived 数组必须转换为长



转换后的长值应为 1282710861



可以任意1帮助我

Now bytDataReceived array have to convert to long

after convert the long value should be 1282710861

can any1 help me

推荐答案

使用BitConverter.ToInt64方法 [ ^ ]







它不起作用，因为你'你的数组中有4个字节，要转换为long，你需要8个字节。

所以，使用 BitConverter.ToInt32方法 [ ^ ]将这些字节转换为Int32，然后转换为Int64。

但重要的是：

Hi,

Use the BitConverter.ToInt64 Method[^]



It doesn''t work because you''ve 4 bytes in your array, and to convert to a long, you need 8 bytes.
So, use the BitConverter.ToInt32 Method[^] to convert these bytes to an Int32, and then cast to an Int64.
But important:

AnnuBhai写道：

AnnuBhai wrote:

bytDataReceived（0）= 76


bytDataReceived（1）= 116


bytDataReceived（2）= 157


bytDataReceived（3）= 77

bytDataReceived(0)=76

bytDataReceived(1)=116

bytDataReceived(2)=157

bytDataReceived(3)=77

如果将该字节数组转换为整数，则不会得到1282710861.

这是1282710861的正确字节数组：

If you convert that byte array to an integer, you don''t will get 1282710861.
This is the correct byte array for 1282710861:

bytDataReceived(0)=76
bytDataReceived(1)=157
bytDataReceived(2)=116
bytDataReceived(3)=77

希望这有帮助。

Hope this helps.

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