关于xmlschema帮助的问题 [英] question about xmlschema help

问题描述

我在msdn。 

中找到了一个示例来创建xmlschema：

  using  System; 
 使用 System.Xml; 
 使用 System.Xml.Schema; 
 
  class  XMLSchemaExamples 
 {
  public   static   void  Main（）
 {
 
 XmlSchema schema =  new  XmlSchema（）; 
 
  //< xs：element name =" cat" type =" xs：string" />  
 XmlSchemaElement elementCat =  new  XmlSchemaElement（）; 
 schema.Items.Add（elementCat）; 
 elementCat.Name = " cat" ; 
 elementCat.SchemaTypeName =  new  XmlQualifiedName（" string" ，" HTTP：//www.w3.org/2001/XMLSchema" ）; 
 
  //< xs：element name =" dog" type =" xs：string" />  
 XmlSchemaElement elementDog =  new  XmlSchemaElement（）; 
 schema.Items.Add（elementDog）; 
 elementDog.Name = " dog" ; 
 elementDog.SchemaTypeName =  new  XmlQualifiedName（" string" ，" HTTP：//www.w3.org/2001/XMLSchema" ）; 
 
  //< xs：element name =" redDog" substitutionGroup = QUOT;狗" />  
 XmlSchemaElement elementRedDog =  new  XmlSchemaElement（）; 
 schema.Items.Add（elementRedDog）; 
 elementRedDog.Name = " redDog" ; 
 elementRedDog.SubstitutionGroup =  new  XmlQualifiedName（" dog" ）; 
 
  //< xs：element name =" brownDog" substitutionGroup =" dog" />  
 XmlSchemaElement elementBrownDog =  new  XmlSchemaElement（）; 
 schema.Items.Add（elementBrownDog）; 
 elementBrownDog.Name = " brownDog" ; 
 elementBrownDog.SubstitutionGroup =  new  XmlQualifiedName（" dog" ）; 
 
 
  //< xs：element name =" pets">  
 XmlSchemaElement elementPets =  new  XmlSchemaElement（）; 
 schema.Items.Add（elementPets）; 
 elementPets.Name = " pets" ; 
 
  //< xs：complexType>  
 XmlSchemaComplexType complexType =  new  XmlSchemaComplexType（）; 
 elementPets.SchemaType = complexType; 
 
  //< xs：choice minOccurs =" 0" maxOccurs =" unbounded">  
 XmlSchemaChoice choice =  new  XmlSchemaChoice（）; 
 complexType.Particle = choice; 
 choice.MinOccurs = 0; 
 choice.MaxOccursString = " unbounded" ; 
 
  //< xs：element ref =" cat" />  
 XmlSchemaElement catRef =  new  XmlSchemaElement（）; 
 choice.Items.Add（catRef）; 
 catRef.RefName =  new  XmlQualifiedName（" cat" ）; 
 
  //< xs：element ref =" dog" />  
 XmlSchemaElement dogRef =  new  XmlSchemaElement（）; 
 choice.Items.Add（dogRef）; 
 dogRef.RefName =  new  XmlQualifiedName（" dog" ）; 
 
 XmlSchemaSet schemaSet =  new  XmlSchemaSet（）; 
 schemaSet.ValidationEventHandler + =  new  ValidationEventHandler（ValidationCallbackOne）; 
 schemaSet.Add（schema）; 
 schemaSet.Compile（）; 
 
 XmlSchema compiledSchema =  null ; 
 
  foreach （XmlSchema schema1  in  schemaSet.Schemas（））
 {
 compiledSchema = schema1; 
} 
 
 XmlNamespaceManager nsmgr =  new  XmlNamespaceManager（ new  NameTable（ ））; 
 nsmgr.AddNamespace（" xs" ，" http：//www.w3.org / 2001 / XMLSchema的" ）; 
 compiledSchema.Write（Console.Out，nsmgr）; 
} 
 
  public   static   void  ValidationCallbackOne（ object  sender，ValidationEventArgs args）
 {
 Console.WriteLine（args.Message）; 
} 
} 

我想获取xmlschema innertext。

我如何将innertext放入文本框？

 thx 

解决方案

< blockquote>

写入StringWriter而不是写入Console.Out，然后调用ToString（）并分配给TextBox的Text属性：

 

  using（StringWriter sw = new StringWriter（））

{

   compiledSchema.Write（sw ，nsmgr）;

   Textbox1.Text = sw.ToString（）;

}

I found a example from msdn. 

to wirte a xmlschema:

using System;
using System.Xml;
using System.Xml.Schema;

class XMLSchemaExamples
{
  public static void Main()
  {

    XmlSchema schema = new XmlSchema();

    // <xs:element name="cat" type="xs:string"/>
    XmlSchemaElement elementCat = new XmlSchemaElement();
    schema.Items.Add(elementCat);
    elementCat.Name = "cat";
    elementCat.SchemaTypeName = new XmlQualifiedName("string", "http://www.w3.org/2001/XMLSchema");

    // <xs:element name="dog" type="xs:string"/>
    XmlSchemaElement elementDog = new XmlSchemaElement();
    schema.Items.Add(elementDog);
    elementDog.Name = "dog";
    elementDog.SchemaTypeName = new XmlQualifiedName("string", "http://www.w3.org/2001/XMLSchema");

    // <xs:element name="redDog" substitutionGroup="dog" />
    XmlSchemaElement elementRedDog = new XmlSchemaElement();
    schema.Items.Add(elementRedDog);
    elementRedDog.Name = "redDog";
    elementRedDog.SubstitutionGroup = new XmlQualifiedName("dog");

    // <xs:element name="brownDog" substitutionGroup ="dog" />
    XmlSchemaElement elementBrownDog = new XmlSchemaElement();
    schema.Items.Add(elementBrownDog);
    elementBrownDog.Name = "brownDog";
    elementBrownDog.SubstitutionGroup = new XmlQualifiedName("dog");


    // <xs:element name="pets">
    XmlSchemaElement elementPets = new XmlSchemaElement();
    schema.Items.Add(elementPets);
    elementPets.Name = "pets";

    // <xs:complexType>
    XmlSchemaComplexType complexType = new XmlSchemaComplexType();
    elementPets.SchemaType = complexType;

    // <xs:choice minOccurs="0" maxOccurs="unbounded">
    XmlSchemaChoice choice = new XmlSchemaChoice();
    complexType.Particle = choice;
    choice.MinOccurs = 0;
    choice.MaxOccursString = "unbounded";

    // <xs:element ref="cat"/>
    XmlSchemaElement catRef = new XmlSchemaElement();
    choice.Items.Add(catRef);
    catRef.RefName = new XmlQualifiedName("cat");

    // <xs:element ref="dog"/>
    XmlSchemaElement dogRef = new XmlSchemaElement();
    choice.Items.Add(dogRef);
    dogRef.RefName = new XmlQualifiedName("dog");

    XmlSchemaSet schemaSet = new XmlSchemaSet();
    schemaSet.ValidationEventHandler += new ValidationEventHandler(ValidationCallbackOne);
    schemaSet.Add(schema);
    schemaSet.Compile();

    XmlSchema compiledSchema = null;

    foreach (XmlSchema schema1 in schemaSet.Schemas())
    {
      compiledSchema = schema1;
    }

    XmlNamespaceManager nsmgr = new XmlNamespaceManager(new NameTable());
    nsmgr.AddNamespace("xs", "http://www.w3.org/2001/XMLSchema");
    compiledSchema.Write(Console.Out, nsmgr);
  }

  public static void ValidationCallbackOne(object sender, ValidationEventArgs args)
  {
    Console.WriteLine(args.Message);
  }
}

i want get the xmlschema innertext.

how can i put the innertext into a Textbox?

thx

解决方案

Write to a StringWriter instead of writing to Console.Out, then call ToString() and assign to the Text property of your TextBox:

 

 using (StringWriter sw = new StringWriter())

{

   compiledSchema.Write(sw, nsmgr);

   Textbox1.Text = sw.ToString();

}

这篇关于关于xmlschema帮助的问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！