如何获得警报触发通知 [英] How to get an alarm to trigger a notification
问题描述
我需要设置，将触发一次重复报警，启动一个通知。
I need to set a repeating alarm that will once fired, launch a notification.
步骤：
- 我需要一些最新资讯，（只是有一个想法，也许我应该推出一个意图，以显示设置闹钟功能）的接口。的细节的产品是需要被送入报警方法的日期时间字符串。
- 当设置报警我需要创建它的一个引用，因此它可以被用户删除。 （或者也许不是，什么是最好的做法吗？也许用户只能删除报警部分报警）
- 当警报响起的通知将被创建。
我不明朗的报警系统是如何工作的。报警probaly应该保持沉默，可能与振动。是直截了当设置？
I'm uncertain of how the alarm system works. The alarm probaly should be silent, maybe with vibration. Is that straight forward to setup?
我是否需要服务或将广播reciever做的工作？
Do I need a service or will a broadcast reciever do the job?
基本上我只需要几个指针。我在思考这个正确？是否有一个教程在那里（我还没有发现任何东西）。先谢谢了。
Basically I just need a few pointers. Am I thinking about this correctly? Is there a tutorial out there (I haven't found anything). Thanks in advance.
推荐答案
下面是我如何在我的应用程序使用AlarmService的演练。
Here is a walkthrough on how I use an AlarmService in my app.
-
设置一个AlarmManager在x分钟火。
Set up an AlarmManager to fire in x minutes.
在响应报警，启动服务。
In response to the alarm, start a service.
创建您的通知，并让您的服务为自己设定了一个新的报警在另一个x分钟再次触发。
Create your notification and have your service set itself up with a new Alarm to fire again in another x minutes.
该服务自行关闭。
1
Intent alarmIntent = new Intent(this, MyAlarm.class);
long scTime = 60* 10000;// 10 minutes
PendingIntent pendingIntent = PendingIntent.getBroadcast(this, 0, alarmIntent, 0);
AlarmManager alarmManager = (AlarmManager) getSystemService(ALARM_SERVICE);
alarmManager.set(AlarmManager.RTC_WAKEUP, System.currentTimeMillis() + scTime, pendingIntent);
2
public class MyAlarm extends BroadcastReceiver
{
@Override
public void onReceive(Context context, Intent intent) {
Log.d("Alarm Recieved!", "YAAAY");
Intent i = new Intent(context, InviteService.class);
context.startService(i);
}
}
3。
public class InviteService extends IntentService
{
/**
* A constructor is required, and must call the super IntentService(String)
* constructor with a name for the worker thread.
*/
public InviteService() {
super("InviteService");
}
/**
* The IntentService calls this method from the default worker thread with
* the intent that started the service. When this method returns, IntentService
* stops the service, as appropriate.
*/
@Override
protected void onHandleIntent(Intent intent) {
String ns = Context.NOTIFICATION_SERVICE;
NotificationManager mNotificationManager = (NotificationManager) getSystemService(ns);
int icon = R.drawable.logo;
CharSequence tickerText = "New Invite!";
long when = System.currentTimeMillis();
Notification notification = new Notification(icon, tickerText, when);
notification.flags |= Notification.FLAG_AUTO_CANCEL;
notification.defaults |= Notification.DEFAULT_VIBRATE;
Context context = getApplicationContext();
CharSequence contentTitle = "Title";
CharSequence contentText = "Text";
Intent notificationIntent = new Intent(this, Destination.class);
Bundle partyBundle = new Bundle();
PendingIntent contentIntent = PendingIntent.getActivity(this, SOME_ID, notificationIntent, 0);
notification.setLatestEventInfo(context, contentTitle, contentText, contentIntent);
int NOTIFICATION_ID = SOME_ID;
Log.d("NOTIFICATION_ID", "" + NOTIFICATION_ID);
mNotificationManager.notify(NOTIFICATION_ID, notification);
4（在同一个班）
4.(In the Same Class)
Intent alarmIntent = new Intent(this, MyAlarm.class);
long scTime = 60*1000;//mins
PendingIntent pendingIntent = PendingIntent.getBroadcast(this, 0, alarmIntent, 0);
AlarmManager alarmManager = (AlarmManager) getSystemService(ALARM_SERVICE);
alarmManager.set(AlarmManager.RTC_WAKEUP, System.currentTimeMillis() + scTime, pendingIntent);
stopService(intent);
}
}
希望这有助于！
Hope this helps!
修改
为什么要使用一个服务？
Why use a Service?
这不是明智的做法是做多的处理在广播接收器。虽然你可以在BroadcastReciever做一些处理，它是安全做一个服务，你可以找到在这个计算器问题的广播接收器VS服务
It's not wise to do much processing in the BroadcastReceiver. Although you can do some processing in the BroadcastReciever, it is safer to do this in a Service, you can find some information in this StackOverflow question BroadcastReceiver vs Service
这篇关于如何获得警报触发通知的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
