通过code安卓魂在Android模拟器电脑的IP地址 [英] Fetch ip address of pc on android emulator through code android

问题描述

我想在Android模拟器通过code我的电脑的IP地址....或者告诉我才达到连接的局域网内所有设备的IP地址来标识每一个唯一...... 。请帮我理清这个问题。

I want to get the ip address of my pc in android emulator through code....or tell me to achive ip address of all devices connected in a lan to identify each one uniquely .......please help me to sort out this problem

在此先感谢

推荐答案

以上功能仅通过检查ARP高速缓存，其中IP地址将取决于如何每一个连接到设备添加一个个都是可能的。使用低于code和检查。只要把按钮与正确的名称，并调用该方法点击

The above functions are possible only by checking the arp cache where the IP address will be added one by one depending on how each one connect to the device. USe the below code and check. Just put button with proper name and call this method on click

    public void getClientList() {

    int macCount = 0;
    BufferedReader br = null;
    try {
        br = new BufferedReader(new FileReader("/proc/net/arp"));
        String line;
        while ((line = br.readLine()) != null) {
            String[] splitted = line.split(" +");

            if (splitted != null && splitted.length >= 4) {
                // Basic sanity check
                String mac = splitted[3];

                if (mac.matches("..:..:..:..:..:..")) {
                    macCount++;
                    ClientList.add("Client(" + macCount + ")");
                    IpAddr.add(splitted[0]);
                    HWAddr.add(splitted[3]);
                    Device.add(splitted[5]);
                    Toast.makeText(
                            getApplicationContext(),
                            "Mac_Count  " + macCount + "   MAC_ADDRESS  "
                                    + mac, Toast.LENGTH_SHORT).show();
                    for (int i = 0; i < splitted.length; i++)
                        System.out.println("Addressssssss     "
                                + splitted[i]);
                }
            }
        }
        // ClientList.remove(0);

    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        try {
            br.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

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