如何在javascript中验证只接受8-10位数的phonenumber，也不应该从数字1开始 [英] how to validate in javascript to accept phonenumber only from 8-10 digits and also should not start with digit 1

问题描述

function email()
{
  if (document.getElementById("<%=txtEmail.ClientID%>").value=="")
      {
                 alert("Please enter your Email ID");
                 document.getElementById("<%=txtEmail.ClientID%>").focus();
                 return false;
      }

  
    var emailPat = /^(\".*\"|[A-Za-z]\w*)@(\[\d{1,3}(\.\d{1,3}){3}]|[A-Za-z]\w*(\.[A-Za-z]\w*)+)$/;
     var emailid=document.getElementById("<%=txtEmail.ClientID%>").value;
     var matchArray = emailid.match(emailPat);
     if (matchArray == null)
    {
               alert("Your email address seems incorrect. Please try again.");
               document.getElementById("<%=txtEmail.ClientID%>").focus();
               return false;
    }
    }

推荐答案

/;
var emailid = document.getElementById（<％= txtEmail.ClientID ％> ）。value;
var matchArray = emailid.match（emailPat）;
if（matchArray == null）
{
alert（>您的电子邮件地址似乎不正确。请再次尝试 。 ）;
document.getElementById（<％= txtEmail.ClientID ％> ）。focus（）;
返回false;
}
}

/; var emailid=document.getElementById("<%=txtEmail.ClientID%>").value; var matchArray = emailid.match(emailPat); if (matchArray == null) { alert("Your email address seems incorrect. Please try again."); document.getElementById("<%=txtEmail.ClientID%>").focus(); return false; } }

我会选择这样的正则表达式：



[02-9] \d {7,9}



将匹配任何以1开头的数字字符串，后面跟着7到9位数字。

I would go for a regular expression like that :

[02-9]\d{7,9}

which will match any string beginning with a digit except 1, followed by 7 to 9 digits.

这篇关于如何在javascript中验证只接受8-10位数的phonenumber，也不应该从数字1开始的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！