在处理exe文件时隐藏表单并在关闭应用程序后显示表单 [英] Hide the form during processing an exe file and show form after close the application

问题描述

请帮助我，我是编程的初学者，我需要知道如何做到这一点（如果你对我的解释很糟糕，对不起我的英语）



Process.Start（My.exe）时隐藏表单;关闭应用程序后重新显示

Please kindly help me, Im a beginner to programming and i need to know how to do this (sorry about my English if you got sucks with my explanation)

Hide form when Process.Start(My.exe); and re show after close the Application

private void simpleButton2_Click(object sender, EventArgs e)
{
    Process.Start("My.exe");
}

i需要在我的应用程序目录中运行一个应用程序，当开始处理exe文件时我需要隐藏运行My.exe时的表单，关闭后显示My.exe

i need to run an application where in my application directory, when start to process the exe file i need to hide the form during run the My.exe, and show after close My.exe

推荐答案

你可以从应用程序启动路径重启你的exe如下所示

You can restart you exe from application start up path like below

ProcessStartInfo Info = new ProcessStartInfo();
      Info.Arguments = "/C \"" + Application.StartupPath + "\\AppRestart.exe" + "\"";
      Info.WindowStyle = ProcessWindowStyle.Normal;
      Info.CreateNoWindow = false;
      Info.FileName = "cmd.exe";
      Process.Start(Info);
      Environment.Exit(0);

显示和隐藏表格的代码

Code for show and hide the form

Form1 obj=new Form1();

显示

Show

obj.show();

隐藏

Hide

obj.hide();

请在任何地方显示和隐藏代码。



希望这有帮助

Please put show and hide code wherever you want.

Hope this helps

您可以等待使用<关闭进程code> process.WaitForExit（） function。

查看示例：

You can wait for a process to close using process.WaitForExit() function.
See a sample example:

private void button1_Click(object sender, EventArgs e)
{
    Process proc = new Process();
    proc.StartInfo.FileName = "notepad";
    proc.Start(); //Starts the process
    this.Hide(); //Hides the form
    proc.WaitForExit(); //Wait until process is exited
    this.Show(); //Shows the form
}

- Amit

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