如何在Crystal报表中生成包含Number值的文本框 [英] how grow a textbox in crystal report which contains Number value

问题描述

Iam在我的c＃应用程序中使用Crystal报表。

我想知道我是否可以增长一个具有数字值的文本框。

在格式对象中它是不可能的。

所以我想知道是否有任何可能的方法来做这个



谢谢

问候

Nirmala Saravanan

Iam using Crystal reports in my c# Application.
I want to know whether i can make grow a text box which has number value.
In format object it is not possible.
So i want to know whether is there any possible way to do that

Thanks
Regards
Nirmala Saravanan

推荐答案

您可以尝试以下代码。请让我知道它是否正常工作我在我的应用程序中没有尝试这个但是在网上得到它...



Dim cryRpt As New CrystalDecisions.CrystalReports .Engine.ReportDocument

cryRpt.Load（Server.MapPath（" .. \ ReportPrint \ CrystalReport.rpt"））

cryRpt.Database.Tables（0 ）.SetDataSource（dsHdr.Tables（0））

cryRpt.Database.Tables（1）.SetDataSource（dsDtl.Tables（0））

CrystalReportViewer1.Visible = True

CrystalReportViewer1.ReportSource = cryRpt



Dim myTextObjectOnReport As CrystalDecisions.CrystalReports.Engine.TextObject



myTextObjectOnReport = CType（cryRpt.ReportDefinition.ReportObjects.Item（" Text4"），CrystalDecisions.CrystalReports.Engine.TextObject）



myTextObjectOnReport.Text ="你想要文本对象的文本

myTextObjectOnReport.Width = 500

myTextObjectOnReport.Color = Drawing.Color.BlueViolet



让'尝试相同... Thanx

You can try the following code. Please let me know is it working or not I haven''t try this in my application but got it on net...

Dim cryRpt As New CrystalDecisions.CrystalReports.Engine.ReportDocument
cryRpt.Load(Server.MapPath("..\ReportPrint\CrystalReport.rpt"))
cryRpt.Database.Tables(0).SetDataSource(dsHdr.Tables(0))
cryRpt.Database.Tables(1).SetDataSource(dsDtl.Tables(0))
CrystalReportViewer1.Visible = True
CrystalReportViewer1.ReportSource = cryRpt

Dim myTextObjectOnReport As CrystalDecisions.CrystalReports.Engine.TextObject

myTextObjectOnReport = CType(cryRpt.ReportDefinition.ReportObjects.Item("Text4"), CrystalDecisions.CrystalReports.Engine.TextObject)

myTextObjectOnReport.Text = "Text you want for text object"
myTextObjectOnReport.Width = 500
myTextObjectOnReport.Color = Drawing.Color.BlueViolet

let''s try the same... Thanx

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