通过从组合框中选择任何表来填充datagridview [英] populate datagridview by selecting any table from combo box
本文介绍了通过从组合框中选择任何表来填充datagridview的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我使用以下代码在combobox中显示我的sql db表的名称...现在我想要数据当我从组合框中点击任何这些表名时...我dgv填充该表的内容
i have used the following code for displaying names of my sql db tables in combobox...now i want dat when i click on any of these table names from combo box..my dgv populates with that table''s contents
private void Form1_Load(object sender, EventArgs e)
{
String strConnection = "Data Source=HP\\SQLEXPRESS;database=MK;Integrated Security=true";
SqlConnection con = new SqlConnection(strConnection);
try
{
con.Open();
SqlCommand sqlCmd = new SqlCommand();
sqlCmd.Connection = con;
sqlCmd.CommandType = CommandType.Text;
sqlCmd.CommandText = "Select table_name from information_schema.tables";
SqlDataAdapter sqlDataAdap = new SqlDataAdapter(sqlCmd);
DataTable dtRecord = new DataTable();
sqlDataAdap.Fill(dtRecord);
comboBox1.DataSource = dtRecord;
comboBox1.DisplayMember = "TABLE_NAME";
con.Close();
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
推荐答案
你好mayuri
i认为它会对你有所帮助
hello mayuri
i think it will help you
private void comboBox1_SelectedIndexChanged(object sender, EventArgs e)
{
string table_name=combobox1.selecteditem.tostring(); //or can use string table_name= combox1.text
con.Open();
SqlDataAdapter da = new SqlDataAdapter("select * from " + table_name + " ",con);
DataSet ds = new DataSet();
da.Fill(ds);
dgv.DataSource = ds.Tables[0];
dgv.DataBind();
con.Close();
}
乐于帮助
happy to help
确保你的gridview属性AutoGeneratedColumns = true,因为你动态绑定记录到gridview ...
Make sure that your gridview property "AutoGeneratedColumns=true", becouse you dynamically bind records to the gridview...
private void comboBox1_SelectedIndexChanged(object sender, EventArgs e)
{
if (comboBox1.SelectedValue != null)
{
PopulateGridView(comboBox1.SelectedValue.ToString());
}
}
并确保在上面的代码comboBox1.SelectedValue中是你的表名..
and make sure that in above code "comboBox1.SelectedValue" is your table name..
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