实施OnTouchListener上的LinearLayout - Android的发展 [英] Implementing OnTouchListener on LinearLayout - Android Development

问题描述

public class UnitConverterActivity extends Activity implements OnTouchListener {
/** Called when the activity is first created. */
LinearLayout mLinearLayout;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    mLinearLayout = new LinearLayout(this);

    ImageView i = new ImageView(this);
    i.setImageResource(R.drawable.mainmenu);
    //i.setAdjustViewBounds(false);
    i.setScaleType(ScaleType.FIT_XY);
    i.setLayoutParams(new Gallery.LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT));

    mLinearLayout.addView(i);
    setContentView(mLinearLayout);
    //setContentView(R.layout.main);
}

@Override
public boolean onTouch(View arg0, MotionEvent arg1) {
    // TODO Auto-generated method stub
    return false;
}
}

我用上面的方法来加载图像的主菜单我试图创造。图像具有四个区域，每个将被用于调用该应用的特定功能。现在我想实现在这些领域的触摸界面。我知道如何定义用于这一目的的像素范围，但我在就如何落实OnTouchListner在图像上的损失。请帮我在这方面。

I have used the above method to load an image for the main menu I am trying to create. The image has four areas and each will be used to call a particular function of the app. Now I am trying to implement touch interface on those areas. I know how to define the range of pixels for that purpose but I am at loss on how to implement OnTouchListner on the image. Please help me in this regard.

推荐答案

如果你的形象被分成四个长方形季度（说）

If your image was split into four rectangular quarters (say)

再有的onCreate：

then in onCreate have:

i.setOnTouchListener(this);

和你的听众，像这样（说明唯一原则）：

and for your listener, something like this (illustrates the principle only):

@Override
public boolean onTouch(View v, MotionEvent mev) {
    int width = v.getWidth();
    int height = v.getHeight();
    float x = mev.getX();
    float y = mev.getY();
    String msg;
    if (x < width / 2) {
        if (y < height / 2)
            msg = "Top left quarter";
        else
            msg = "Bottom left quarter";

    } else {
        if (y < height / 2)
            msg = "Top right quarter";
        else
            msg = "Bottom right quarter";
    }
    Toast.makeText(this, msg, Toast.LENGTH_SHORT).show();
    return false;
}

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