C＃UWP TIMER [英] C# UWP TIMER

问题描述

字符串o =" X =" + vals [0] +" Y =" + vals [1] +" Z =" + vals [2]; 
 if（vals [0]！=" 225.0"&& vals [1]！=" 225.0"&& vals [2]！=" 225.0"）
 {
 txtTimer.Interval = TimeSpan.FromSeconds（3）; 
 txtTimer.Tick + = txtTimer_Tick; 
 txtTimer.Start（）; 
} 

 private void txtTimer_Tick（object sender，object e）
 {
 updateText.Text =" Connection好的。你已经准备好开始锻炼了。他们继续第3步。" 
} 

我想设置一个计时器，如果我的x，y，z值是225.0，它将显示一个文本。但文本将在3秒后显示。这是我做的代码，但它不起作用。为什么会这样？

解决方案

您的帖子未启动一般性讨论。所以，最好把它作为一个问题。

你的行：

  txtTimer  。  Interval     =     TimeSpan  。  FromSeconds  （  3  ）;  

甚至不应该编译，因为属性Interval是double类型，而方法FromSeconds（）返回TimeSpan对象。你可以尝试：

  txtTimer  。  Interval     =     TimeSpan  。  FromSeconds  （  3  ）。TotalMilliseconds;  

wizend

String o = "X=" + vals[0] + "  Y=" + vals[1] + "  Z=" + vals[2];
                    if (vals[0] != "225.0" && vals[1] != "225.0" && vals[2] != "225.0")
                    {
                        txtTimer.Interval = TimeSpan.FromSeconds(3);
                        txtTimer.Tick += txtTimer_Tick;
                        txtTimer.Start(); 
                    }

private void txtTimer_Tick(object sender, object e)
        {
            updateText.Text = "Connection okay. You're ready to start your exercise.\nProceed to Step 3.";
        }

I want to set up a timer where if my x,y,z values are 225.0 , it will display a text. But the text will be shown 3 seconds later. This is the code I did but it doesnt work. Why is this so ?

解决方案

Your post does not launch a General Discussion. So, better make it a Question.

Your line:

txtTimer.Interval = TimeSpan.FromSeconds(3);

shouldn't even compile, because the property Interval is of the type double whereas the method FromSeconds() returns a TimeSpan object. You could try:

txtTimer.Interval = TimeSpan.FromSeconds(3).TotalMilliseconds;

wizend

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