弹出警报框自定义 [英] popup alert box as customized
本文介绍了弹出警报框自定义的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
嗨朋友
请帮帮我
什么时候给无效的详细信息显示弹出窗口和显示提醒
即如果我给出无效的登录详细信息(不匹配数据库表)那么我想显示popas(我的自己弹出窗口显示错误measege
我的代码在这里为此提供解决方案
hi friends
please help me
when give invalid details display popup and show alert
i.e if i given invalid details for login (don''t match db table) then i want to dispaly popus as customized(my own popup) in that box display error measege
my code is here and give solution for this
<link rel="stylesheet" href="css/jquery-ui.css" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6/jquery.min.js"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
window.$required = $('<div></div>').dialog({
autoOpen: false,
title: 'Required Information'
});
});
</script>
<script type="text/javascript">
function validate_login ( )
{
valid = true;
if ( document.login.user.value == "" )
{
// alert ( "Please fill the user name." );
$required.html("Please fill the user name.").dialog('open');
valid = false;
}
else if ( document.login.pass.value == "" )
{
$required.html("Please fill the password.").dialog('open');
valid = false;
}
return valid;
}
</script>
</head>
<td >
<form name="login" method="post" action="login.php" onSubmit="return validate_login( );">
<div class="webmail-bg">
<table width="301" border="0" cellspacing="0" cellpadding="0">
<tr>
<td height="28" align="left" valign="top">Username :</td>
</tr>
<tr>
<td><label>
<input name="user" id="sPerson" type="text" class="email-txt-field" value="" />
</label></td>
</tr>
<tr>
<td height="38" align="left" valign="middle">Password :</td>
</tr>
<tr>
<td><label>
<input type="password" name="pass" type="text" class="email-txt-field" value="" />
</label></td>
</tr>
---------->用DB表检查登录详细信息的代码-------->
---------->code for check for login details with DB table-------->
<?php
ob_start();
include "db.php";
$username=$_POST["user"];
$password=$_POST["pass"];
$username=strip_tags(stripslashes($username));
$password=strip_tags(stripslashes($password));
//now md5 the password
//$pass=md5($password);
$mysqlqry="select username,password from admin_login where username='".$username."' and password='".$password."'";
//echo $mysqlqry;
$result = mysql_query($mysqlqry);
$count=mysql_affected_rows();
//echo "Result is ".$result;
//echo $count;
if(!$result)
{
echo("<P>Can't execute the query.</P>");
echo("<P>Error performing query: " . mysql_error() . "</P>");
include "index.php";
exit();
}
else
if($count==1)
{
setcookie("login","User",time()+2*3600);
header('Location: adminhome.php');
}
else {
echo "<script> alert('invalid username or password')</script>";
//echo "Invalid Username or Password.<br>";
include "index.php";}?>
推荐答案
(document).ready(function(){
window。
(document).ready(function() { window.
required =
required =
('< div > < / div < span class =code-keyword>> ')。dialog({
autoOpen:false,
title:'Required Information'
});
});
< / script >
('<div></div>').dialog({ autoOpen: false, title: 'Required Information' }); }); </script>
<script type="text/javascript">
function validate_login ( )
{
valid = true;
if ( document.login.user.value == "" )
{
// alert ( "Please fill the user name." );
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