指定的小孩已经有一个父。你必须呼吁孩子的父母第一次removeView（）（Android版） [英] The specified child already has a parent. You must call removeView() on the child's parent first (Android)

问题描述

在我的应用程序，我经常两个布局之间进行切换。该错误是发生在下面张贴的布局。

In my app, I have to switch between two layouts frequently. The error is happening in the layout posted below.

在我的布局叫做第一次，有没有存在的任何错误，一切都很好。当我然后调用不同的布局（空的），之后打电话给我布置了第二次，它给了我以下错误：

When my layout is called the first time, there isn't occuring any error and everything's fine. When I then call a different layout (a blank one) and afterwards call my layout a second time, it gives me the following error:

> FATAL EXCEPTION: main
>     java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.

我的布局 - code是这样的：

My layout-code looks like this:

    tv = new TextView(getApplicationContext()); // are initialized somewhere else
    et = new EditText(getApplicationContext()); // in the code


private void ConsoleWindow(){
        runOnUiThread(new Runnable(){

     @Override
     public void run(){

        // MY LAYOUT:
        setContentView(R.layout.activity_console);
        // LINEAR LAYOUT
        LinearLayout layout=new LinearLayout(getApplicationContext());
        layout.setOrientation(LinearLayout.VERTICAL);
        setContentView(layout);

        // TEXTVIEW
        layout.addView(tv); //  <==========  ERROR IN THIS LINE DURING 2ND RUN
        // EDITTEXT
        et.setHint("Enter Command");
        layout.addView(et);
        }
    }
}

我知道这个问题已经被问过，但它并没有在我的情况有所帮助。

I know this question has been asked before, but it didn't help in my case.

推荐答案

该错误消息说，你应该做的。

The error message says what You should do.

// TEXTVIEW
if(tv.getParent()!=null)
    ((ViewGroup)tv.getParent()).removeView(tv); // <- fix
layout.addView(tv); //  <==========  ERROR IN THIS LINE DURING 2ND RUN
// EDITTEXT

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