Android联系人过滤器无效 [英] Android contact filter not working

问题描述

我有一些示例代码，我想在其上添加搜索过滤器，在您键入任何字母进行过滤后，它不会显示已过滤的联系人或者它不会更新列表视图，任何人都可以对其进行说明，谢谢。

 import ........ 
 
 ContactAdapter objAdapter; 
 private ListView listView; 
 EditText inputSearch; 
 private List< contactbean> list = new ArrayList< contactbean>（）; 
 
 @Override 
 protected void onCreate（Bundle savedInstanceState）{
 super.onCreate（savedInstanceState）; 
 setContentView（R.layout.activity_main）; 
 
 listView =（ListView）findViewById（R.id.list）; 
 listView.setOnItemClickListener（this）; 
 inputSearch =（EditText）findViewById（R.id.inputSearch）; 
 listView =（ListView）findViewById（R.id.list）; 
 
 Cursor phones = getContentResolver（）。query（
 ContactsContract.CommonDataKinds.Phone.CONTENT_URI，null，null，null，null）; 
 while（phones.moveToNext（））{
 String name = phones.getString（phones .getColumnIndex（ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME））; 
 
 String phoneNumber = phones.getString（phones .getColumnIndex（ContactsContract.CommonDataKinds.Phone.NUMBER））; 
 
 ContactBean objContact = new ContactBean（）; 
 objContact.setName（name）; 
 objContact.setPhoneNo（phoneNumber）; 
 list.add（objContact）; 
 
} 
 phones.close（）; 
 
 objAdapter = new ContactAdapter（MainActivity.this，R.layout.alluser_row，list）; 
 listView.setAdapter（objAdapter）; 
 if（null！= list&& list.size（）！= 0）{
 Collections.sort（list，new Comparator< contactbean>（）{
 
 @Override 
 public int compare（ContactBean lhs，ContactBean rhs）{
 return lhs.getName（）。compareTo（rhs.getName（））; 
} 
}）; 
} else {
 showToast（No Contact Found !!!）; 
} 
 
 inputSearch.addTextChangedListener（new TextWatcher（）{
 
 @Override 
 public void onTextChanged（CharSequence cs，int arg1，int arg2，int arg3）{
 //当用户更改Text 
 MainActivity.this.objAdapter.getFilter（）。filter（cs）; 
} 
 
 @Override 
 public void beforeTextChanged（CharSequence arg0，int arg1，int arg2，int arg3）{
 // TODO自动生成的方法stub 
} 
 
 @Override 
 public void afterTextChanged（Editable arg0）{
 // TODO自动生成的方法stub 
} 
}）; 
} 

解决方案

您可能想在设置listView后尝试添加此行

 inputSearch =（EditText）findViewById（R.id.inputSearch）; 
 listView =（ListView）findViewById（R.id.list）; 
 .. 
 

加上这个

  //  启用对给定ListView内容的过滤 
 listView.setTextFilterEnabled（true）; 

还改变这个

  @覆盖 
  public   void  onTextChanged（CharSequence cs， int  arg1， int  arg2， int  arg3）{ 
  //  当用户更改文本 
 MainActivity。此 .objAdapter.getFilter（）过滤器（CS）。 
} 
 

到



< pre lang =java> @ Override
public void onTextChanged（CharSequence cs， int arg1， int arg2， int arg3）{
// 当用户更改文本
objAdapter.getFilter（）。filter（cs.toString（））;
}

我也在仿真器中找到了我必须按一封信然后返回给它工作，但我的模拟器目前用中文出于某种原因，不要问....



希望它有帮助



/ Darren

I got some sample code and i wanted to add search filter on it, after you type any letter to filter it won''t show the filtered contacts or it won''t update the listview, can anyone say something on it, thanks.

import ........

   ContactAdapter objAdapter;
   private ListView listView;
   EditText inputSearch;
   private List<contactbean> list = new ArrayList<contactbean>();

    @Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);       

listView = (ListView) findViewById(R.id.list);
listView.setOnItemClickListener(this);
    inputSearch = (EditText) findViewById(R.id.inputSearch);
    listView = (ListView) findViewById(R.id.list);

    Cursor phones = getContentResolver().query(
            ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, null);
    while (phones.moveToNext()) {
        String name = phones.getString(phones           .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));

        String phoneNumber = phones.getString(phones                            .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));

        ContactBean objContact = new ContactBean();
        objContact.setName(name);
        objContact.setPhoneNo(phoneNumber);         
        list.add(objContact);

    }
    phones.close();

   objAdapter = new ContactAdapter(MainActivity.this, R.layout.alluser_row, list);
   listView.setAdapter(objAdapter);
      if (null != list && list.size() != 0) {
        Collections.sort(list, new Comparator<contactbean>() {

            @Override
            public int compare(ContactBean lhs, ContactBean rhs) {
                return lhs.getName().compareTo(rhs.getName());
            }
        });
       } else {
    showToast("No Contact Found!!!");
 }

    inputSearch.addTextChangedListener(new TextWatcher() {

    @Override
    public void onTextChanged(CharSequence cs, int arg1, int arg2, int arg3) {
        // When user changed the Text
        MainActivity.this.objAdapter.getFilter().filter(cs);
    }

    @Override
    public void beforeTextChanged(CharSequence arg0, int arg1, int arg2, int arg3)                   {
        // TODO Auto-generated method stub   
    }

    @Override
    public void afterTextChanged(Editable arg0) {
        // TODO Auto-generated method stub
    }
});
  }

解决方案

You might want to try adding this line just after you setup your listView

inputSearch = (EditText) findViewById(R.id.inputSearch);
listView = (ListView) findViewById(R.id.list);
..

add this

//enables filtering for the contents of the given ListView
  listView.setTextFilterEnabled(true);

Also Change this

@Override
  public void onTextChanged(CharSequence cs, int arg1, int arg2, int arg3) {
      // When user changed the Text
      MainActivity.this.objAdapter.getFilter().filter(cs);
  }

To

@Override
   public void onTextChanged(CharSequence cs, int arg1, int arg2, int arg3) {
       // When user changed the Text
       objAdapter.getFilter().filter(cs.toString());
   }

I also found in the emulator I had to press a letter and return to get it to work but then my emulator is currently in Chinese for some reason, don''t ask....

Hope it helps

/Darren

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