通过URL和标题在Android的网页视图 [英] passing url and title to a webview in android

问题描述

我在一个项目中工作的地方我有一个项目列表视图谷歌，雅虎，必应等物质点击网页视图，必须装入相应的url.my问题的每个产品，我已创建了一个项目列表视图它，但我需要加载，如果我点击谷歌的所有urls.ie只有一个类web视图必须加载谷歌网页，如果我preSS雅虎必须在同一webview.i加载页面雅虎想通过点击的项目的URL到下一个页面（web视图）

i'm working in a project where i have a listview with items google,yahoo,bing etc.on clicking on each item a webview must be loaded with the corresponding url.my problem is that i have created a listview with items on it but i need only one class for loading all the urls.ie if i click on google the webview must load the google page and if i press yahoo it must load the yahoo page in the same webview.i want to pass the url of the clicked item to the next page(webview)

public class MainActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    populateListView();
    clickEvent();

}

private void populateListView() {
    String[] str={"Google","yahoo", "bing"};
    ArrayAdapter<String>adapter=new ArrayAdapter<String>(this, R.layout.textview,str);
    ListView list=(ListView)findViewById(R.id.listviewone);
    adapter.notifyDataSetChanged();
    list.setAdapter(adapter);


}
private void clickEvent() {
    final ListView list=(ListView)findViewById(R.id.listviewone);   

    list.setOnItemClickListener(new AdapterView.OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position,
                long id) {
             view.setSelected(true); 
            switch( position )
            {
               case 0:   Intent newActivity0 = new Intent(MainActivity.this, Mywebpage.class);     
                         startActivity(newActivity0);   
                         break;

            }              
        }

    });
}

我webpage.java

my webpage.java

public class Mywebpage extends Activity {
public void onCreate(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
setContentView(R.layout.webviewpage);
        WebView wbView = (WebView) findViewById(R.id.WebView);
        wbView.getSettings().setJavaScriptEnabled(true); 
        wbView.loadUrl("http://www.google.com");

}
}

} }

推荐答案

要发送的标题和网址到的WebView类传球意图额外给的WebView类，即。重写你的开关情况下

To send title and url to webview class pass intent extra to webview class,i.e. Rewrite your switch case as

Intent newActivity0 = new Intent(MainActivity.this, Mywebpage.class);
newActivity0.putExtra("title", str[position]);
switch (position) {
    case 0:
        newActivity0.putExtra("url", "http://www.google.com");
        break;
    case 1:
        newActivity0.putExtra("url", "http://www.yahoo.com");
        break;
    case 2:
        newActivity0.putExtra("url", "http://www.bing.com");
        break;
}

startActivity(newActivity0);

和定义

 String[] str={"Google","yahoo", "bing"};

作为类变量，而不是 populateListView 方法。

和在 Mywebpage 类获得意图为

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.webviewpage);

    Bundle extras = getIntent().getExtras();
    String title, url;

    if (extras != null) {
        title = extras.getString("title");
        url = extras.getString("url");

        WebView wbView = (WebView) findViewById(R.id.WebView);
        wbView.getSettings().setJavaScriptEnabled(true);
        wbView.loadUrl(url);
    } //rest code

编辑：

请确保您连接到互联网，并已按照清单权限：

Make sure you are connected to internet and you have following permission in the manifest:

<uses-permission android:name="android.permission.INTERNET"></uses-permission> 

这篇关于通过URL和标题在Android的网页视图的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！