如何使用调度计时器和消息框创建幸运抽奖（除了调度计之外的任何其他建议也值得赞赏！） [英] how do I create a lucky draw using dispatch timer and messagebox(Any other suggestion on methods other than dispatchtimer is appreciated too!)

问题描述

嗨！因为我目前还在学习，我正在研究的项目需要一个幸运抽奖轮。我已将WPF集成到我的Windows窗体项目中。目前我的WPF加载事件被写为（下面的代码），之后我需要一个按钮，当点击时在3-10秒之间随机旋转
并提示一个消息框提示用户奖品（从数据库中提取）他/她赢了。谢谢！ （欢迎使用其他方法进行任何建议！）

private void Grid_Loaded（object sender，RoutedEventArgs e）

        {

            myMediaElement.Play（）;

            var da = new DoubleAnimation（0,360，new Duration（TimeSpan.FromSeconds（6）））;

            var rt = new RotateTransform（）;

            ellipse.RenderTransform = rt;

            ellipse2.RenderTransform = rt;

            Spin.RenderTransform = rt;

            ellipse.RenderTransformOrigin = new Point（0.5,0.5）;

            ellipse2.RenderTransformOrigin = new Point（0.5,0.5）;

            Spin.RenderTransformOrigin = new Point（0.5,0.5）;

            da.RepeatBehavior = RepeatBehavior.Forever;

            rt.BeginAnimation（RotateTransform.AngleProperty，da）;

}

我试过用过故事板（如下所示）在按钮上完成后，它只是提示一个消息框说'祝贺你赢了！' 

< EventTrigger RoutedEvent =" Button.Click">

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; < BeginStoryboard>

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; < Storyboard x：Name =" Mystoryboard"完成= QUOT; Mystoryboardcompleted" FillBehavior =" Stop">

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; < DoubleAnimation Storyboard.TargetName =" ellipse"

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; Storyboard.TargetProperty = QUOT;（UIElement.RenderTransform）（RotateTransform.Angle）"。 AutoReverse =" False"

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; AccelerationRatio = QUOT 1 QUOT;持续时间=" 0：0：4英寸通过= QUOT; 2000" />

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; < DoubleAnimation Storyboard.TargetName =" ellipse"

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; Storyboard.TargetProperty = QUOT;（UIElement.RenderTransform）（RotateTransform.Angle）"。 AutoReverse =" False"

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; DecelerationRatio = QUOT 1 QUOT;持续时间=" 0：0：4英寸通过= QUOT; 1200" />< / Storyboard>

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; < / BeginStoryboard>

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; < / EventTrigger>

  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; < /Button.Triggers>

解决方案

嗨DerpyShaun，

首先将相关用户添加到列表< KeyValuePair < int ，
string > >。

 
 int angle = 5040; 
 for（int i = 0; i< 8; i）
 {
 
 // 
 angle + = 45; 
 _ListAngle.Add（angle）; 
 
 _ListUser.add（ new     KeyValuePair  <   int  ，    string  >（ angle   ，   用户名 ），  
 ）
} 
 

其次，您可以通过角度键检索相关的用户名。

 
 int _Index = 0; 
 int _OldAngle = 0; 
 private void btnStartTurntable_Click（object sender，RoutedEventArgs e）
 {
 btnStartTurntable.IsEnabled = false; 
 _Index = _Random.Next（0,8）; 
 Storyboard sb =（故事板）this.FindResource（" zhuandong"）; 
 sb.Completed  -  = this.sb_Completed; 
 sb.Completed = new EventHandler（sb_Completed）; 
（（SplineDoubleKeyFrame）（（DoubleAnimationUsingKeyFrames）sb.Children [0]）。KeyFrames [0]）。Value = _OldAngle; 
（（SplineDoubleKeyFrame）（（DoubleAnimationUsingKeyFrames）sb.Children [0]）。KeyFrames [3]）。Value = _ListAngle [_Index]; 
 sb.Begin（）; 
} 
 
 void sb_Completed（对象发送者，EventArgs e）
 {
 DispatcherTimer dt = new DispatcherTimer（）; 
 dt.Interval = TimeSpan.FromSeconds（0.3）; 
 dt.Tick =委托
 {
 dt.Stop（）; 
 _OldAngle =（_ ListAngle [_Index]％360）; 
 btnStartTurntable.IsEnabled = true; 
 
 //通过角度列表的索引提醒相关消息。 
 // AwardProcess（GetAward（_ListAngle [_Index]））; 
}; 
 dt.Start（）; 
} 
 

祝你好运，

张龙

Hi! Because I am currently still learning, a project that I am working on requires a lucky draw wheel. I have integrated a WPF into my windows form project. Currently my WPF load event is written as(code below), after that i need a button when clicked spins randomly between 3-10 seconds and prompts a messagebox that prompts user a prize(extracted from database) that he/she has won. thank you! (Any suggestion on how i can use other method to do this is welcome!)

private void Grid_Loaded(object sender, RoutedEventArgs e)
        {
            myMediaElement.Play();
            var da = new DoubleAnimation(0, 360, new Duration(TimeSpan.FromSeconds(6)));
            var rt = new RotateTransform();
            ellipse.RenderTransform = rt;
            ellipse2.RenderTransform = rt;
            Spin.RenderTransform = rt;
            ellipse.RenderTransformOrigin = new Point(0.5, 0.5);
            ellipse2.RenderTransformOrigin = new Point(0.5, 0.5);
            Spin.RenderTransformOrigin = new Point(0.5, 0.5);
            da.RepeatBehavior = RepeatBehavior.Forever;
            rt.BeginAnimation(RotateTransform.AngleProperty, da);

}

I have tried using a storyboard(shown below) on a button however after it is done, it just prompts a messagebox saying 'congratulations you have won!' 

<EventTrigger RoutedEvent="Button.Click">
                    <BeginStoryboard>
                        <Storyboard x:Name="Mystoryboard" Completed="Mystoryboardcompleted" FillBehavior="Stop">
                            <DoubleAnimation Storyboard.TargetName="ellipse"
                                             Storyboard.TargetProperty="(UIElement.RenderTransform).(RotateTransform.Angle)" AutoReverse="False"
                                             AccelerationRatio="1" Duration="0:0:4" By="2000" />
                            <DoubleAnimation Storyboard.TargetName="ellipse"
                                             Storyboard.TargetProperty="(UIElement.RenderTransform).(RotateTransform.Angle)" AutoReverse="False"
                                             DecelerationRatio="1" Duration="0:0:4" By="1200" /></Storyboard>
                    </BeginStoryboard>
                </EventTrigger>
            </Button.Triggers>

解决方案

Hi DerpyShaun,

Firstly add related user to a List<KeyValuePair<int, string>>.

 int angle = 5040;
for (int i = 0; i < 8; i  )
{
// 
     angle  += 45;
     _ListAngle.Add(angle);
    _ListUser.add(new KeyValuePair<int, string>(angle, username),
)
}

Secondly, you could retrieve related username via the key of angle.

        int _Index = 0;
        int _OldAngle = 0;
        private void btnStartTurntable_Click(object sender, RoutedEventArgs e)
        {
            btnStartTurntable.IsEnabled = false;
            _Index = _Random.Next(0, 8);
            Storyboard sb = (Storyboard)this.FindResource("zhuandong");
            sb.Completed -= this.sb_Completed;
            sb.Completed  = new EventHandler(sb_Completed);
            ((SplineDoubleKeyFrame)((DoubleAnimationUsingKeyFrames)sb.Children[0]).KeyFrames[0]).Value = _OldAngle;
            ((SplineDoubleKeyFrame)((DoubleAnimationUsingKeyFrames)sb.Children[0]).KeyFrames[3]).Value = _ListAngle[_Index];
            sb.Begin();
        }
 
        void sb_Completed(object sender, EventArgs e)
        {
            DispatcherTimer dt = new DispatcherTimer();
            dt.Interval = TimeSpan.FromSeconds(0.3);
            dt.Tick  = delegate 
            {
                dt.Stop();
                _OldAngle = (_ListAngle[_Index] % 360);
                btnStartTurntable.IsEnabled = true;
//alert related message via Angle list's index.
                //AwardProcess(GetAward(_ListAngle[_Index]));
            };
            dt.Start();
        }

Best regards,

Zhanglong

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