将unix shell脚本转换为C ++ [英] Convert unix shell script to C++
问题描述
我正在Linux操作系统上开发基于USB树的应用程序,因为我正在将其中一个shell脚本转换为C ++。但是我在shell脚本方面没有太多经验
我在这个剧本中感到困惑
I am developing a USB tree based application on a Linux operating system for that I am converting one of the shell script to C++. But I am not that much experienced in shell script
I am confused in this script
if [ $level -gt 0 ]; then
port=$((${devpath##*[-.]} - 1))
else
port=0
fi
请在linux下的usb-devices脚本中解释一下这个脚本的含义。我如何编写C / C ++代码等同于此。我被困在这个$(($ {devpath ## * [ - 。]} - 1))剧本系列
任何帮助将不胜感激...
Any one please explain me the meaning of this script in usb-devices script in linux. How I can write a C/C++ code to equivalent of this. i am stuck in this $((${devpath##*[-.]} - 1)) line of script
Any help will be appreciated...
推荐答案
level -gt 0 ];然后
port =
level -gt 0 ]; then port=
((
{devpath ## * [ - 。]} - 1 ))
else
port = 0
fi
{devpath##*[-.]} - 1)) else port=0 fi
任何人请在linux中的usb-devices脚本中解释这个脚本的含义。我如何编写C / C ++代码等同于此。我陷入了这个
Any one please explain me the meaning of this script in usb-devices script in linux. How I can write a C/C++ code to equivalent of this. i am stuck in this
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