如何使spannable多个文本？ [英] How to make spannable with multiple text?

问题描述

String sentence="this is @part 1 and #here another and #another one @user  #newone @itsme ";

    textView.setMovementMethod(LinkMovementMethod.getInstance());
    textView.setText(addClickablePart(sentence), BufferType.SPANNABLE);


    private SpannableStringBuilder addClickablePart(String str) {
    SpannableStringBuilder ssb=new SpannableStringBuilder(str);

    int idx1=Math.min(str.indexOf("@"),str.indexOf("#") );

    int idx2=0;
    while (idx1!=-1) {
        idx2=str.indexOf(" ", idx1) + 1;

        final String clickString=str.substring(idx1, idx2);
        ssb.setSpan(new ClickableSpan() {

            @Override
            public void onClick(View widget) {
                Toast.makeText(getApplicationContext(), clickString,
                        Toast.LENGTH_SHORT).show();
            }
        }, idx1, idx2, 0);

        idx1=Math.min(str.indexOf("#", idx2),str.indexOf("@", idx2) );

    }

    return ssb;
}

对于第一五个字却留下最后一个（@itsme）其工作罚款。
它左派只有最后一个（不管什么串的长度）

its working fine for first five words but left last one (@itsme). it lefts only last one (no matter whats the length of string).

推荐答案

把一个条件在while语句检查字符串的大小。

put one condition in while statement for checking string size.

我觉得 IDX2 在最后一个循环是0，因为 str.indexOf（）为-1，那么-1 +1 = 0。

i think idx2 in last loop is 0, because str.indexOf() is -1 then -1 +1 = 0.

所以你检查，如果 IDX2 0然后进行点击，直到最后的尺寸

so you check that if idx2 is 0 then make clickable until last of size

使用以下code：

while (idx1 != -1) {

            idx2 = sentence.indexOf(" ", idx1) + 1;

            if(idx2 == 0)  
                 idx2 = sentence.length(); // or str.lenght()-1 

            idx2 = sentence.indexOf(" ", idx1) + 1;

            final String clickString=str.substring(idx1, idx2);
            ssb.setSpan(new ClickableSpan() {

                @Override
                public void onClick(View widget) {
                     Toast.makeText(getApplicationContext(), clickString,
                          Toast.LENGTH_SHORT).show();
              }
         }, idx1, idx2, 0);

            idx1 = FindMin(idx2+1 , sentence);
        }

FindMin是：

FindMin is:

public int FindMin(int i2 , String mystr)
    {
        int idx1 = mystr.indexOf("@" , i2);
        int idx2 = mystr.indexOf("#" , i2);


        int minIndex;
        if(idx1 >= 0 && idx2 >= 0 )
         minIndex  =  Math.min(mystr.indexOf("@" , i2) ,mystr.indexOf("#" , i2) );

        else if (idx1 >= 0)
          minIndex = idx1;

        else
           minIndex = idx2;

        return minIndex;
    }

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