如果有人知道c ++，请帮助我？ [英] Please help me if anyone know c++?

问题描述

假设我有两个二进制值01000100和01000010.

我想像这样压缩它们：

Suppose i have two binary values 01000100 and 01000010.
I want to compress them like this:

01000100 = 1
01000010 = 0

压缩后2bytes将转换为2bits

并将它们解压缩如下：

After compress the 2bytes would be converted to 2bits
and decompress them like:

1 = 01000100
0 = 01000010

解压后2bits将转换为2bytes



实际上我想压缩2byte（二进制）到2bits.And after解压缩数据再次转换为2byte。

我如何在visual basic中执行此操作。我是计算机编程的新手

After decompress the 2bits would be converted to 2bytes

Actually i want to compress 2byte(binary) to 2bits.And after decompress the data again convert to 2byte.
How can i do it in visual basic. I am a new in computer programming

推荐答案

如果你只有2个输入和2个输出值，那么非常简单。

Pretty simple if you only have 2 input and 2 output values.

char Compress(char in)
{
  if(68 == in) return 1;  // 01000100 -> 1
  if(66 == in) return 0;  // 01000010 -> 0
  return -1;              // invalid
}

char Decompress(char in)
{
  if(1 == in) return 68;  // 1 -> 01000100
  if(0 == in) return 66;  // 0 -> 01000010
  return -1;              // invalid
}

你的问题描述我觉得这里的问题是......

Your problem description I think was the problem here...

你做不到 - 除了你已经给出的琐碎案例很简单：

You can''t do it - except in the trivial case you are giving already which is easy:

1) Is value equal to 0?
2) if yes, output value is 01000010
3) if no, output value is 01000100

两位只能容纳4个值： br />

Two bits can only hold 4 values:

00
01
10
11

所以其他252你可以进入8位的可能组合无处可存储。压缩算法通过查找数字模式（实质上）并且需要一定量的开销来存储有关压缩方法的信息 - 只有8位数据，没有足够的信息来确定模式 - 并且有了开销，你最终会输出比输入更长！

So the other 252 possible combinations you can get into 8 bits have nowhere to be stored. Compression algorithms work by finding patterns in numbers (in essence) and require an amount of overhead to store information about the compression method - with only eight bits of data there is insufficient information for a pattern to be determined - and with overhead you would end up with a longer output than input!

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