重定数字的转换 [英] Reagarding conversion of numbers

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本文介绍了重定数字的转换的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述







我正在为Windows手机和桌面写一个板球应用程序我也有小查询我需要计算运行率,但我面临转换十进制到int和我需要十进制值到int数。请参考下面的逻辑和示例



运行所需的运行

------------------------------ x 6 =所需的运行率

球剩余





例如,需要43次跑才能赢得4.2分。

然后需要运行率将是: -



运行所需的运行= 43

剩余球= 4.2超过=(4 x 6)+ 2 = 26球





运行需要赢得

------------ ------------------ x 6 =所需的运行率

球剩余





43

---- x 6 = 9.92

26

Hi,


I am writting one cricket app for windows phone and desktop also i have small query its i need to calculate the run rate but i am facing in the conversion decimal to int and i need that decimal value to int number.Please refer the below logic and example

Runs required to win
------------------------------ x 6 = Required run rate
Balls Remaining


For example 43 runs are required to win in 4.2 overs.
Then Required run rate would be:-

Runs required to win = 43
Balls Remaining = 4.2 overs = (4 x 6) + 2 = 26 balls


Runs required to win
------------------------------ x 6 = Required run rate
Balls Remaining


43
---- x 6 = 9.92
26

推荐答案

假设你想要一个十进制运行鼠e(9.92)转换为最接近的整数:

Assuming that you want a decimal run rate (9.92) converted up to the nearest integer:
Decimal precise = 9.92M;
int roundedUp = (int)Math.Ceiling(precise);


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