图片上传到服务器 [英] Uploading image onto server
本文介绍了图片上传到服务器的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
公共类上传{ProgressDialog对话框= NULL;
INT serverResponse code = 0;
字符串uploadFilePath = NULL;
字符串uploadFileName = NULL;
弦乐味精= NULL;
字符串upLoadServerUri =http://192.168.1.179/index.php;
保护MainActivity语境;公共上传（MainActivity上下文）{
this.context =背景;
}公众诠释uploadFile（字符串sourceFileUri）{
字符串文件名= sourceFileUri; HttpURLConnection的康恩= NULL;
DataOutputStream类DOS = NULL;
字符串lineEnd =\\ r \\ n;
串twoHyphens = - ;
字符串边界=*****;
INT读取动作，方bytesAvailable，缓冲区大小;
字节[]缓冲区;
INT MAXBUFFERSIZE = 1 * 1024 * 1024;
文件的资源文件=新的文件（sourceFileUri）; 如果（！sourceFile.isFile（））{ context.dialog.dismiss（）; 返回0; }其他{
尝试{ //打开一个URL连接到这个Servlet
的FileInputStream的FileInputStream =新的FileInputStream（的资源文件）;
网址URL =新的URL（upLoadServerUri）; //打开HTTP连接的URL
康恩=（HttpURLConnection类）url.openConnection（）;
conn.setDoInput（真）; //允许输入
conn.setDoOutput（真）; //允许输出
conn.setUseCaches（假）; //不要使用缓存副本
conn.setRequestMethod（POST）;
conn.setRequestProperty（连接，保持活动）;
conn.setRequestProperty（ENCTYPE，多部分/表单数据）;
conn.setRequestProperty（内容类型，的multipart / form-data的;边界=+边界）;
conn.setRequestProperty（uploaded_file，文件名）; DOS =新的DataOutputStream类（conn.getOutputStream（））; dos.writeBytes（twoHyphens +边界+ lineEnd）;
dos.writeBytes（内容处置：表格数据;名称= \\uploaded_file \\;文件名= \\
+文件名+\\+ lineEnd）; dos.writeBytes（lineEnd）; //创建最大大小的缓冲区
参考bytesAvailable = fileInputStream.available（）; BUFFERSIZE = Math.min（方bytesAvailable，MAXBUFFERSIZE）;
缓冲区=新的字节[缓冲区大小] //读取文件，并将其写入形式...
读取动作= fileInputStream.read（缓冲液，0，缓冲区大小）; 而（读取动作大于0）{ dos.write（缓冲液，0，缓冲区大小）;
参考bytesAvailable = fileInputStream.available（）;
BUFFERSIZE = Math.min（方bytesAvailable，MAXBUFFERSIZE）;
读取动作= fileInputStream.read（缓冲液，0，缓冲区大小）; } //发送文件数据后necesssary多部分的表单数据...
dos.writeBytes（lineEnd）;
dos.writeBytes（twoHyphens +边界+ twoHyphens + lineEnd）; //服务器的响应（code和消息）
serverResponse code = conn.getResponse code（）;
串serverResponseMessage = conn.getResponseMessage（）; Log.i（一个UploadFile，HTTP响应是：
+ serverResponseMessage +：+ serverResponse code）; 如果（serverResponse code == 200）{
InputStream为= conn.getInputStream（）;
RD的BufferedReader =新的BufferedReader（新的InputStreamReader（是））;
串线;
StringBuffer的响应=新的StringBuffer（）;
而（（行= rd.readLine（））！= NULL）{
response.append（线）;
response.append（'\\ r'）;
}
rd.close（）;
context.q_no.setText（响应）; fileInputStream.close（）;
dos.flush（）;
dos.close（）; context.runOnUiThread（新的Runnable（）{
公共无效的run（）{ 弦乐味精=是; //context.messageText.setText(msg）;
Toast.makeText（背景下，文件上传完成。
Toast.LENGTH_SHORT）.show（）;
}
}）; }
}赶上（MalformedURLException的前）{ Log.e（上传文件到服务器，错误：+ ex.getMessage（），除息）;
}赶上（例外五）{ context.dialog.dismiss（）;
e.printStackTrace（）;
Log.e（上传文件到服务器异常，异常
+ e.getMessage（），E）;
}
context.dialog.dismiss（）;
返回serverResponse code; }
}
}
我想上面code捕捉到的图像，并上传到PHP server.it工作fine.when我上传图片服务器返回一个value.but当我尝试这个codeI得到下面的图像后，异常被上载到服务器和服务器响应。
10月7日至27日：50：55.303：W / System.err的（4649）：android.view.ViewRootImpl $ CalledFromWrongThreadException：只有创建视图层次原来的线程可以触摸它意见。
解决方案
您正在运行正常，上传上一个单独的线程（AsyncTask的？） - 不错。但是，任何时候你的UI（互动 .dialog.dismiss（）， .setText（...），等等），你需要在UI线程上运行此。
public class Upload {
ProgressDialog dialog = null;
int serverResponseCode = 0;
String uploadFilePath = null;
String uploadFileName = null;
String msg = null;
String upLoadServerUri = " http://192.168.1.179/index.php";
protected MainActivity context;
public Upload(MainActivity context) {
this.context = context;
}
public int uploadFile(String sourceFileUri) {
String fileName = sourceFileUri;
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File(sourceFileUri);
if (!sourceFile.isFile()) {
context.dialog.dismiss();
return 0;
} else {
try {
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("uploaded_file", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if (serverResponseCode == 200) {
InputStream is = conn.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
String line;
StringBuffer response = new StringBuffer();
while ((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
context.q_no.setText(response);
fileInputStream.close();
dos.flush();
dos.close();
context.runOnUiThread(new Runnable() {
public void run() {
String msg = "yes";
//context.messageText.setText(msg);
Toast.makeText(context, "File Upload Complete.",
Toast.LENGTH_SHORT).show();
}
});
}
} catch (MalformedURLException ex) {
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
context.dialog.dismiss();
e.printStackTrace();
Log.e("Upload file to server Exception", "Exception : "
+ e.getMessage(), e);
}
context.dialog.dismiss();
return serverResponseCode;
}
}
}
i tried above code to capture image and upload onto php server.it works fine.when i upload image server return a value.but when i try this code i get following exception after image is uploaded onto the server and the server response.
07-27 10:50:55.303: W/System.err(4649): android.view.ViewRootImpl$CalledFromWrongThreadException: Only the original thread that created a view hierarchy can touch its views.
解决方案
You're correctly running upload on a separate thread (AsyncTask?) -- good. However, anytime you interact with the UI (.dialog.dismiss(), .setText(...), etc), you will need to run this on the UI thread.
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