如何解耦Observable和Observer之间的关系 [英] how to decouple the relationship between Observable and Observer

问题描述

您好，

以下代码来自 Tiny-0601 。

public delegate void mcEventHandler();

class Cat
    {
        string cName;
        
        public event mcEventHandler CatCryEvent; 
        public Cat(string name)
        {
            cName = name;
        }
        
        public void Cry()
        {
            Console.WriteLine(cName+"coming");
            Console.ReadLine();
            CatCryEvent();
        }
    }

	
    class Mouse
    {
        public string mName;
        public Mouse(Cat cat)
        {
            cat.CatCryEvent += Run;
            cat.CatCryEvent += new mcEventHandler(See);
        }

        private void Run()
        {
            Console.WriteLine("Cat is coming，"+mName+"I will be on my way");
        }
        private void See()
        {
            Console.WriteLine("See if the cat is still in");
            Console.ReadLine();
        }
    }

    class Program
    {
        static void Main(string[] args)
        {
            Cat cat1 = new Cat("Tom");
            Mouse m1 = new Mouse(cat1);
            cat1.Cry();
        }
    }

我想知道如何在Class Mouse中建立关系，而不是在Main方法中。 我想打电话给"cat1.Cry（）;"使用Event提升Mouse.Run（）和Mouse.See（），而不使用"Mouse m1 = new Mouse（cat1）"。

I want to know how to build the relationship in Class Mouse, not in the Main method.  I want to just call the "cat1.Cry();" to raise the Mouse.Run() and Mouse.See() by using Event, without using "Mouse m1 = new Mouse(cat1)".

谢谢。

Thank you.

推荐答案

虽然你可以这样做，但用例是什么？因此它不再是观察者模式。还要记住，你需要 类似于动作的寄存器类型。在鼠标类中执行此操作时，这意味着向鼠标类添加耦合，这会适得其反。

While you can do this, what is the use-case? Cause then it is no longer the observer pattern. Also keep in mind, you need  a register type like action. When doing this in the mouse class, this means adding coupling to the mouse class, which is counterproductive.

这篇关于如何解耦Observable和Observer之间的关系的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！