最后显示数字肯定 [英] Displaying Numbers at last for sure

问题描述

亲爱的论坛，





我对这类概念有些新意.......其实赞成我需要的是当我在QLineEdit中给出一些值时，如果它不包含数字它应该至少有四位数它应该引发错误......希望你能得到我...... Actualy我有在Java中完成相同的工作并且它工作正常......请找到供您参考的代码......任何解决方案都会很明显.....在此先感谢.....



[代码]





公共课堂考试{

public static void main（String [] args）{

String s =abcd1000231231232131212;

System.out.println（check（s））;

}





public static boolean check（String s）{



if（s.length（）> = 4）{

String s1 = s.substring（s.length（） - 4，s.length（））;

System.out.println（s1）;

试试{

Inte ger.parseInt（s1）;



if（Integer.parseInt（s1）== 0）{

返回false;

}

返回true;

} catch（NumberFormatException e）{

返回false;

}



}

返回false;

}



}







[/ code]







问候，

解决方案

使用以下代码

  string  s1 =   GHGHGHJJH1238; 
 
  int  x =  Int32  .Parse（s1.Substring（s1.Length） -   4 ， 4 ））; 
 MessageBox.Show（x.ToString（））;  //  显示消息或任何你想要的内容 

好​​运;

亲爱的Mantu，





感谢您的回复......您认为您发送的代码如何运作......实际上它的抛出错误如



---->''Int32''未在此范围内声明



----> ;''class QString''没有名为''Substring''的成员'



---->''class QString''没有名为''的成员长度''



---->请求''x'中的成员''ToString''，这是非类型''int ''



实际上SubString不支持donno为什么.........任何解决方案都会很明显.....在此先感谢...





问候，

Dear Forums,


I am somewhat new to this type of concept.......Actually the favour that i need is when i give some value in the QLineEdit at the end it should have atleast four digits if it doesn''t contain digits it should raise an error......hope you got me....Actualy i have done the same in Java and it works fine......Please find the code for your reference......Any solution would be appreciable.....Thanks in Advance.....

[code]


public class test {
public static void main(String[] args) {
String s = "abcd1000231231232131212";
System.out.println(check(s));
}


public static boolean check(String s ) {

if(s.length()>=4){
String s1 = s.substring(s.length()-4, s.length());
System.out.println(s1);
try {
Integer.parseInt(s1);

if(Integer.parseInt(s1) == 0){
return false;
}
return true;
} catch (NumberFormatException e) {
return false;
}

}
return false;
}

}



[/code]



Regards,

解决方案

Use the following code

string s1 = "GHGHGHJJH1238";

          int x = Int32.Parse(s1.Substring(s1.Length - 4, 4));
          MessageBox.Show(x.ToString());// show message or whatever you want

Best of luck;

Dear Mantu,


Thanks for the reply......How do you think the code that you sent will work....Actually its throwing errors like

---->''Int32'' was not declared in this scope

---->''class QString'' has no member named ''Substring''

---->''class QString'' has no member named ''Length''

---->request for member ''ToString'' in ''x'', which is of non-class type ''int''

Actually SubString is not supporting donno why.........Any solution would be appreciable.....Thanks in Advance...


Regards,

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