从表单1访问form2 [英] Access form2 from form 1

问题描述

我正在使用visual studio 2012.我正在使用Windows窗体应用程序。在我的申请表中有两种形式。首先，我通过单击按钮从form1访问form2。现在我想通过单击按钮从form2访问form1。但我不能这样做。我知道这对开发人员来说是一个愚蠢的问题，但这对我来说很痛苦。请帮我解决这个问题。在此先感谢..........

I am using visual studio 2012. I am working on windows form application. In my application there are two form. At first I access form2 from form1 by clicking a button. Now I want to access form1 from form2 by clicking a button. But I can''t do this. I know this is a silly problem for developer but this is painful for me. Please help me to solve this problem. Thanks in advance..........

推荐答案

这是关于表单协作的热门问题。最强大的解决方案是在表单类中实现适当的接口，并传递接口引用而不是引用Form的整个实例。有关更多详细信息，请参阅我以前的解决方案：如何以两种形式复制列表框之间的所有项目 [ ^ ]。



另请参阅此处的其他解决方案讨论。如果应用程序足够简单，解决方案就像在一个表单中声明一些 internal 属性并将对一个表单的实例的引用传递给另一个表单的实例一样简单形成。对于更复杂的项目，这种违反严格封装的样式和松散耦合可能会增加代码的意外复杂性并引发错误，因此封装良好的解决方案将是优惠。



另请参阅：

http://en.wikipedia.org/wiki/Accidental_complexity [ ^ ]，

http://en.wikipedia.org/wiki/Loose_coupling [ ^ ]。

-SA

This is the popular question about form collaboration. The most robust solution is implementation of an appropriate interface in form class and passing the interface reference instead of reference to a "whole instance" of a Form. Please see my past solution for more detail: How to copy all the items between listboxes in two forms[^].

Please also see other solutions in this discussion. If the application is simple enough, the solution could be as simple as declaring of some internal property in one form and passing a reference to the instance of one form to the instance of another form. For more complex projects, such violation of strictly encapsulated style and loose coupling could add up the the accidental complexity of the code and invite mistakes, so the well-encapsulated solution would be preferable.

Please see also:
http://en.wikipedia.org/wiki/Accidental_complexity[^],
http://en.wikipedia.org/wiki/Loose_coupling[^].

—SA

如果您正在查看传递数据，在Windows窗体之间传递数据 [ ^ ]可以帮助你。

if you are looking at passing data, Passing Data between Windows Forms[^] should help you out.

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