我怎样才能绑定的整数颜色的像素阵列来使用Android NDK纹理？ [英] How can I bind a pixel array of integer colors to a texture using the Android NDK?

问题描述

我试图端口Android上我的Java的OpenGL code到本地SDK，我需要一个IntBuffer实现。

I'm trying to port my Java OpenGL code on Android to the Native SDK and I need an IntBuffer implementation.

基本上我用Java做的任意整数RGBA像素的彩色阵列加载到纹理是：

Basically what I do in Java to load up an arbitrary integer RGBA pixel color array into a texture is:

    // pixel array
    pixelIntArray = new int[width * height];

    bb = ByteBuffer.allocateDirect(pixelIntArray.length * 4);
    bb.order(ByteOrder.nativeOrder());

    // native buffer
    pixelBuffer = bb.asIntBuffer();

    // push integer array of pixels into buffer
    pixelBuffer.put(pixelIntArray);
    pixelBuffer.position(0);

    // bind buffer to texture
    gl.glTexImage2D(GL10.GL_TEXTURE_2D, 0, GL10.GL_RGBA, width, height, 0,
                GL10.GL_RGBA, GL10.GL_UNSIGNED_BYTE, pixelBuffer);

用C，这样我可以用一个缓冲推纹理四。

in C so that I can push a texture to a quad using a buffer.

目前我只是将它绑定到我用C pixelIntArray和质感散发出来扭曲。

Currently I'm just binding it to my pixelIntArray in C and the texture comes out distorted.

基本上，我需要能够通过类似于Java的NIO类的缓冲区以整数像素阵列结合一系列的颜色到纹理。

Basically I need to be able to bind a series of colors in an integer pixel array to a texture through a buffer similar to Java's NIO class.

推荐答案

我想这可能是如何解决这个问题：

I think this may be how to solve it:

    int length = width * height;

    int* pixels = (int*) malloc(sizeof(int) * length);
    unsigned char * buffer = (unsigned char*) malloc(sizeof(char) * length * 4);

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复制到缓冲区

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    int i, j;

    for (i = 0; i < length; i++) {

        j = 4 * i;

        buffer[j] = (char) (pixels[i] & 0xFF);
        buffer[j + 1] = (char) (pixels[i] >> 8 & 0xFF);
        buffer[j + 2] = (char) (pixels[i] >> 16 & 0xFF);
        buffer[j + 3] = (char) (pixels[i] >> 24 & 0xFF);

    }

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来源

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来源： http://www.c-sharpcorner.com/论坛/主题/ 32972 /

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Source

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From: http://www.c-sharpcorner.com/Forums/Thread/32972/

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