如何插入一个字符串值到对话框消息？ [英] How to insert a string value into a dialog message?

问题描述

我有一个EDITTEXT和一个按钮，如果我输入ABC，然后按下按钮，它就会存储在我的数据库中的值，并会打开一个dielog框说它得到了成功的插入，但在对话框中我也想展示什么让插入，所以继承人code：

 的EditText texto =（EditText上）findViewById（R.id.etAdd）;
最后弦乐resultado = texto.getText（）的toString（）。按钮添加=（按钮）findViewById（R.id.bAdd）;
add.setOnClickListener（新OnClickListener（）{    公共无效的onClick（视图v）{
        // TODO自动生成方法存根
        尝试{
            //睁开OU CRIA UMA数据库COM诺姆德：dbtest.db
            DB = openOrCreateDatabase（dbtest.db，Context.MODE_PRIVATE，NULL）;            尝试{
                db.insert（usuarioorigem，resultado，NULL）;
                ShowMessage（Mensagens，Inserido+ resultado +COM Sucesso的！）;
            } {最后            }
        } {最后        }
    }
}）;
 

解决方案

关键是要检查的<一个成功href=\"http://developer.android.com/reference/android/database/sqlite/SQLiteDatabase.html#insert%28java.lang.String,%20java.lang.String,%20android.content.ContentValues%29\"相对=nofollow>插入操作

 的EditText texto =（EditText上）findViewById（R.id.etAdd）;            按钮添加=（按钮）findViewById（R.id.bAdd）;
            add.setOnClickListener（新OnClickListener（）{                公共无效的onClick（视图v）{
                    // TODO自动生成方法存根
                    尝试{
                        //睁开OU CRIA UMA数据库COM诺姆德：dbtest.db
                        DB = openOrCreateDatabase（dbtest.db，Context.MODE_PRIVATE，NULL）;
                        字符串resultado = texto.getText（）的toString（）。                        尝试{
                            长期结果= db.insert（usuarioorigem，resultado，NULL）;
                            如果（结果== -1）{
                               ShowMessage（错误插入）; //对不起英语在这里，可能是ü可以使用inserido
                            }
                            其他{
                               ShowMessage（Mensagens Inserido+ resultado +COM Sucesso的！）;
                            }
                        }最后{                        }
                }最后{                }
                }
            }）;
    私人无效ShowMessage（弦乐味精）{
        Toast.makeText（这一点，味精，Toast.LENGTH_LONG）.show（）;
    }
 

I have a editText and a button, if i type "abc" and hit the button it will store the value in my database and will open a dielog box saying it got insert successfully but in the dialog box i also want to show what got insert, so heres the code:

EditText texto = (EditText) findViewById(R.id.etAdd);
final String resultado = texto.getText().toString();

Button add = (Button) findViewById(R.id.bAdd);
add.setOnClickListener(new OnClickListener() {

    public void onClick(View v) {
        // TODO Auto-generated method stub
        try {
            //Abre ou Cria uma database com nome de: "dbtest.db"
            db = openOrCreateDatabase("dbtest.db", Context.MODE_PRIVATE, null);

            try {
                db.insert("usuarioorigem", resultado, null);
                ShowMessage("Mensagens","Inserido" +resultado+ "com sucesso!");
            } finally {

            }
        } finally {

        }
    }
});

解决方案

The key is to check for the success of insert operation

   EditText texto = (EditText) findViewById(R.id.etAdd);

            Button add = (Button) findViewById(R.id.bAdd);
            add.setOnClickListener(new OnClickListener() {

                public void onClick(View v) {
                    // TODO Auto-generated method stub
                    try{
                        //Abre ou Cria uma database com nome de: "dbtest.db"
                        db = openOrCreateDatabase("dbtest.db", Context.MODE_PRIVATE, null);
                        String resultado = texto.getText().toString();

                        try{
                            long result = db.insert("usuarioorigem", resultado, null);
                            if(result == -1){
                               ShowMessage("Error in Insert"); //sorry for english here, may be u can use inserido
                            }
                            else{
                               ShowMessage("Mensagens Inserido" +resultado+ "com sucesso!");
                            }
                        }finally{

                        }
                }finally{

                }
                }
            });


    private void ShowMessage(String msg){
        Toast.makeText(this, msg, Toast.LENGTH_LONG).show();
    }

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