要使屏幕兼容性含帆布 [英] Make Screen Compatibility Containing Canvas

问题描述

我在Android的画布上工作。我想在画布上绘制它适合于每一个屏幕的形状。


 如果屏幕尺寸为 320 * 240 ，然后高度和放大器;与宽度为 90 * 90 但

如果 screen_size为> 320 * 240 那么就应该相应增加。

I am working with canvas in android. i want to draw shapes on canvas which fits in every screen.

if screen size is 320 * 240 then height & width with is 90 * 90 but

if screen_size is > 320 * 240 then it should increase accordingly.

假设 screen_size = 1280 * 800 那么就应该增加多少

Suppose screen_size = 1280 * 800 then how much it should increase

我不知道该怎么为这个做

I don't know what to do for this

code为如同

int fixHeight = 240, fixWidth = 320;
Paint paint;
paint = new Paint();
paint.setColor(Color.GREEN);
DisplayMetrics displaymetrics = new DisplayMetrics();
    getWindowManager().getDefaultDisplay().getMetrics(displaymetrics);
int height = displaymetrics.heightPixels;
int width = displaymetrics.widthPixels;
@Override
protected void onDraw(Canvas canvas) {
     if (height <= fixHeight && width <= fixWidth) {
          canvas.drawRect(10, 10, 50, 50, paint);  
     } else {
          // Don't Know What TO Put Here
     }
}

任何一个可以帮助我

Can any one help me

推荐答案

在的onDraw 方法，你可能要检查的布局高度和宽度画布> 和调整draw.height并相应draw.width。

in your onDraw method you might want to check the layout height and width of your canvas and adjust your draw.height and draw.width accordingly.

如果规模已经扩大了屏幕，然后你可以使用一个乘数因子您draw.width和draw.height常量要么乘或绘制前分裂。

If the size has increased for the screen then you can use a multiplying factor to your draw.width and draw.height constants to either multiply or divide before drawing.

编辑： code被张贴后，

After code was posted.

可以说，320 * 240是基本情况下你画高度的矩形40和广度为40即 canvas.drawRect（10，10，50，50，油漆）; 所以左侧，顶部，右侧和底部可以用你的情况进行修改使用以下公式为1280×800的新决议。

Lets say 320*240 is the base case for you to draw a rectangle of height as 40 and breadth as 40 that is canvas.drawRect(10, 10, 50, 50, paint);So left, top, right and bottom can be used to be modified in your case with a new resolution of 1280*800 using the below formula.

320 --> (50 - 10)
1280 --> (x - 10)

所以 X = 10 +（50-10）*三百二十分之一千二百八十零

试着重复wdith相同forumla，你应该得到你的基本坐标。我相信你可以调整你的10，10基于同样的上述公式（这我保持恒定在这里）到新的位置。

Try to repeat the same forumla for wdith and you should get your base co-ordinates. I believe you can adjust your 10, 10(which I am keeping here constant) to a new location based on the same above formula.

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