拆分电子邮件地址以返回姓氏，名字 - 剥离'@' [英] split email address to return last name,first name-strip off '@'

问题描述

   var email =（string）Dts.Variables [" User :: Email"]。Value;

            ; var user = email.Split（new char [] {'。'}，StringSplitOptions.RemoveEmptyEntries）;

             var userString = string.Format（" {0}，{1}"，user [1]，user [0]）;

   var email = (string)Dts.Variables["User::Email"].Value;
            var user = email.Split(new char[]{'.'},StringSplitOptions.RemoveEmptyEntries);
            var userString = string.Format("{0},{1}", user[1], user[0]);

以上商店：user [1]： dave @gmail用户[0]：john

The above stores: user[1]:dave@gmail user[0]:john

电子邮件是：[e-mail]

Email is: [e-mail]

输出应该是dave，john

Output should be dave,john

推荐答案

使用
MailAddress 。将整个字符串传递给构造函数，然后使用属性获取所需的信息。

Use MailAddress for this. Pass the entire string to the constructor and then use the properties to get the information you want.

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