错误代码-2146232060 [英] Error Code -2146232060

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本文介绍了错误代码-2146232060的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

Imports System.Data.SqlClient

Imports System.Data.DataTable

Imports MySql.Data.MySqlClient

Public Class Form1



    Private Sub Label1_Click(发件人为对象,e为EventArgs)处理Label1.Click



   结束分


    Private Sub Button2_Click(发件人为对象,e为EventArgs)处理Button2.Click



   结束分


    Private Sub Button1_Click(发件人为对象,e为EventArgs)处理Button1.Click

        Dim connection As New SqlConnection("Server = localhost; user = root; password = msrp; Database = hotel")



        Dim命令As New SqlCommand("select * from guest,其中username = @username和密码= @ password",连接)



        command.Parameters.Add(" @ username",SqlDbType.VarChar).Value = TextBoxUsername.Text

        command.Parameters.Add(" @ password",SqlDbType.VarChar).Value = TextBoxPassword.Text



        Dim adapter As New SqlDataAdapter(命令)



        Dim table As New DataTable()



        adapter.Fill(table)



  &NBSP; &NBSP; &NBSP;如果table.Rows.Count()< = 0然后



  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; MessageBox.Show("用户名或密码不正确")



  &NBSP; &NBSP; &NBSP;否则



  &NBSP; &NBSP; &NBSP; &NBSP; &NBSP; MessageBox.Show("登录成功")



  &NBSP; &NBSP; &NBSP;结束如果



  &NBSP;结束分


  &NBSP; Private Sub TextBoxUsername_TextChanged(sender As Object,e As EventArgs)Handles TextBoxUsername.TextChanged



  &NBSP;结束点

结束等级

Imports System.Data.SqlClient
Imports System.Data.DataTable
Imports MySql.Data.MySqlClient
Public Class Form1

    Private Sub Label1_Click(sender As Object, e As EventArgs) Handles Label1.Click

    End Sub

    Private Sub Button2_Click(sender As Object, e As EventArgs) Handles Button2.Click

    End Sub

    Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
        Dim connection As New SqlConnection("Server = localhost;user=root;password=msrp;Database = hotel")

        Dim command As New SqlCommand("select * from guest where username = @username and password = @password", connection)

        command.Parameters.Add("@username", SqlDbType.VarChar).Value = TextBoxUsername.Text
        command.Parameters.Add("@password", SqlDbType.VarChar).Value = TextBoxPassword.Text

        Dim adapter As New SqlDataAdapter(command)

        Dim table As New DataTable()

        adapter.Fill(table)

        If table.Rows.Count() <= 0 Then

            MessageBox.Show("Username or password not correct")

        Else

            MessageBox.Show("Login Successful")

        End If

    End Sub

    Private Sub TextBoxUsername_TextChanged(sender As Object, e As EventArgs) Handles TextBoxUsername.TextChanged

    End Sub
End Class

错误说明:

推荐答案

嗨shawanish8,

Hi shawanish8,

根据您的描述,请先确认用户名和密码是否正确,然后尝试重新启动MSSQLSERVER服务,看看它是否可以正常工作。

According to your description, please confirm that the username and password are correct firstly, and then try to restart your MSSQLSERVER service and look if it can work fine.

详细信息步骤是:

1.转到控制面板。

2.搜索服务。

3.从搜索结果中打开本地服务窗口

4.重新启动MSSQLSERVER服务。

The detailed step is:
1.Go to control panel.
2.search for services.
3.Open Local services window from your search results
4.Restart your MSSQLSERVER service.

最好的问候,

Cherry


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