上下文无关语法 [英] Context free grammar

问题描述

我有这种语言需要写上下文无关语法 为此。如果有
提案发送给我 谢谢。

DO     I，j，a：整数     x，y：real     mx [50]：real END DO   I：= 1 < span style ="font-family：Nazli">   j：= 1 < span style ="font-family：Nazli">   打印'输入我'   INPUT I   如果I = 1 < span style ="font-family：Nazli">       j：= j +1       mx [0]：= 5   ELIF    I = 2        j：= j + 4;       mx [0]：= 12    ELSE       myF1（j，i）       mx [0]   ：= 34    结束    在我< 45 的时候做什么          a：= a + 2          DO J：= 1到10 BY 2              DO Z：= 1到20 <跨度风格=" font-family：纳兹勒 "> <跨度风格="">&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP ;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP; k：= j + 2 的 <跨度风格= "">&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP; &NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP; 如果K = 30 < span style ="font-family：Nazli">                  &NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP; BREAK &span style ="">                   ;&NBSP;&NBSP;&NBSP; ELIF K = 40 < span style ="font-family：Nazli">                  &NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP; BREAK 2 &span style ="">                  &NBSP;&NBSP;&NBSP;&NBSP; ELIF K = 50 < span style ="font-family：Nazli">                  &NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP; BREAK 3 &span style ="">                  &NBSP;&NBSP;&NBSP;&NBSP; 结束               结束          结束    结束 结束

函数myF1（m：integer，n：integer） REM这是评论 do   st：string    x：real rem *******    I：整数 end do   st：=“ hello“   print st，m，'hello2'  rem commnet   输入x   如果x = 12 < span style ="font-family：Nazli">     st = st +'yes'   结束   执行  i< m      x：= i * 2 -12   结束   x：= nextF（x）   print x 结束 函数nextF（x：  real）  真实 做 结束 做   返回x * x < span style ="font-family：Nazli"> end < span style ="font-family：Nazli"> *上下字之间没有差异   判别------------------- ：   ，

优先级 运营商------------- ------ （）[] + - ^    From Right to Left           *   / +    - =     < &NBSP;&NBSP;&NBSP; < = <跨度风格= "">&NBSP;&NBSP;&NBSP;&NBSP; >的&NBSP;&NBSP;&NBSP ; > =       <> < p style ="margin-bottom：.0001pt;行高：正常; text-autospace：none"> not 和      或        ：= Constance --------------------------------- -------- '   “ 的&NBSP;&NBSP; '   “    '     “ “   \”   ;  “ '  \'   ;  ' * Key 字（对上下字不敏感）   while while 执行  到[by]   if     elif   ; 其他 end return function * expr =必须中断的循环次数 *如果不存在，则打破内部循环 break [expr [ print 输入 rem integer real string

解决方案

您的问题应该发布到相应的MSDN论坛。 此论坛是关于Microsoft认证的问题。

I have this language that want write context free grammar  for that .if have Proposal send me Thanks.

DO     I , j , a : integer     x , y : real     mx[50] : real END DO   I:=1   j:=1   PRINT 'Enter I '   INPUT I   IF I = 1       j:= j +1       mx[0] := 5   ELIF   I=2        j:=j+4;       mx[0]:=12    ELSE       myF1(j,i)       mx[0]  := 34    END    DO WHILE I <45          a :=a+2          DO J :=1 TO 10 BY 2              DO Z := 1 TO 20                       k:=j+2                       IF K = 30                             BREAK                       ELIF K=40                             BREAK 2                       ELIF K=50                             BREAK 3                       END               end          end    end end

Function myF1( m: integer, n: integer ) REM this is comment do   st: string    x: real rem *******    I: integer end do   st := “hello “   print st , m , 'hello2 '  rem commnet   input x   if x =12     st = st + 'yes'   end   do while  i<m      x :=i *2 -12   end   x := nextF(x)   print x end function nextF(x :  real)  real do end do   return x*x end *Not Different Between Upper And Lower Word   Discriminant------------------- :  ,

Priority of operators------------------- () [] + - ^   From Right To Left       *  / +   - =    <    <=     >    >=      <> not and      or       := Constance----------------------------------------- '   “   '   “   '    “ “  \”   “ '  \'    ' *Key words (Not sensitive to upper and lower word)   do while do  to [by]  if    elif  else end return function *expr=number of loop that must break *if not exist break inner loop break [expr[ print input rem integer real string

解决方案

Your question should be posted to the appropriate MSDN forum.  This forum is for questions relating to Microsoft Certifications.

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