Xsd验证 [英] Xsd validation

问题描述

我有一个简单的xml，其中包含一个元素" Book"其中有3个属性作者，版本，价格。我需要为此创建一个xsd，条件是，如果版本是"免费"，则价格属性不需要具有价值/价格属性，如果版本是"付费"，则价格属性应该是十进制值。

下面提到的是示例xml文件。目前我使用.Net IDE创建xsd并使用自定义数据类型来定义它。我使用xs：choice来执行此操作，但因为它不支持属性而无法正常工作。

Hi,

        I've a simple xml with one element "Book" which have 3 attributes author, edition, price. I need to create an xsd for this based on condition that,
if edition is "free", the price attribute need not have value/price attribute need not be required, and if edition is "paid", the price attribute should be a decimal value.
 
        Below mentioned is the sample xml file. Currently I've used .Net IDE to create xsd and used custom datatype to define this. I used xs:choice to do this, but  was not working as it was not supporting attributes.

<？ xml version = " 1.0 " encoding = " utf-8 " ？>
< 图书馆 xmlns：xsi = " http://www.w3.org/2001/XMLSchema-instance " xsi：noNamespaceS chemaLocation = " sample.xsd " >

<?xml version="1.0" encoding="utf-8"?>
<Library xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="sample.xsd">

< Book name = " 示例书1 " author = " 示例作者1 " < font color ="＃0000ff"size = 2> edition = < font size = 2>" free " 价格 = "" >< / Book >

<Book name="Sample book 1" author="Sample author 1" edition="free" price=""></Book>

< 预订 name = " 示例书2 " author = " 示例作者2 " edition = " ; 付费 " price = " ; 100.0 " >< / Book >

<Book name="Sample book 2" author="Sample author 2" edition="paid" price="100.0"></Book>

< / 图书馆 >

提前致谢...

</Library>

Thanks in advance...

推荐答案

您好Jereesh，

您可能想看看Schematron 。 Schematron允许您使用XPath表达式在XSD中指定其他约束。

您可以在此处找到介绍性文章：

• http://xml.coverpages.org/schematron.html


• http://msdn.microsoft.com/en-us/library/aa468554.aspx

Hi Jereesh,

You might want to have a look at Schematron. Schematron allows you to specify additional constraints in your XSD using XPath expressions.

You find introductary articles here:

• http://xml.coverpages.org/schematron.html
• http://msdn.microsoft.com/en-us/library/aa468554.aspx

问候，
divo

Regards,
divo

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